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Tanya [424]
3 years ago
11

Which of the choices below is not a possible correlation coefficient?

Mathematics
1 answer:
fiasKO [112]3 years ago
8 0

Answer:

The condition for r is the following:

-1 \leq r \leq 1

And for this case if we analyze the options the only impossible value is given by:

1.0528

Because this value is higher than 1 and not satisfy the general limits for r

Step-by-step explanation:

The correlation coefficient is a measure of dispersion and is a value between -1 and 1, and is defined as:

r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}

The condition for r is the following:

-1 \leq r \leq 1

And for this case if we analyze the options the only impossible value is given by:

1.0528

Because this value is higher than 1 and not satisfy the general limits for r

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The table below shows the number of points Josh scored in each basketball game of the season.
MrRissso [65]

Answer:

◻️B. The value of the mode is the least value of the data.

Step-by-step explanation:

The mode is the data value that appears most often

5,7,9,5,18,6,8,5

Arranging the data from smallest to largest

5,5,5,6,7,8,9,18

The number that appears most often is 5

This is the smallest value of the data

5 0
3 years ago
Z=y+mx. Solve for x. I need the answer fast
Simora [160]
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        z-y
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8 0
3 years ago
Assume that you have a sample of n 1 equals 6​, with the sample mean Upper X overbar 1 equals 50​, and a sample standard deviati
tigry1 [53]

Answer:

t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656

df=6+5-2=9

p_v =P(t_{9}>2.656) =0.0131

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

Step-by-step explanation:

Data given

n_1 =6 represent the sample size for group 1

n_2 =5 represent the sample size for group 2

\bar X_1 =50 represent the sample mean for the group 1

\bar X_2 =38 represent the sample mean for the group 2

s_1=7 represent the sample standard deviation for group 1

s_2=8 represent the sample standard deviation for group 2

System of hypothesis

The system of hypothesis on this case are:

Null hypothesis: \mu_1 \leq \mu_2

Alternative hypothesis: \mu_1 > \mu_2

We are assuming that the population variances for each group are the same

\sigma^2_1 =\sigma^2_2 =\sigma^2

The statistic for this case is given by:

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}

The pooled variance is:

S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}

We can find the pooled variance:

S^2_p =\frac{(6-1)(7)^2 +(5 -1)(8)^2}{6 +5 -2}=55.67

And the pooled deviation is:

S_p=7.46

The statistic is given by:

t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656

The degrees of freedom are given by:

df=6+5-2=9

The p value is given by:

p_v =P(t_{9}>2.656) =0.0131

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

4 0
3 years ago
Find the measure of each<br> angle in the isosceles<br> trapezoid.<br> D<br> A<br> 136⁰<br> B<br> с
icang [17]

Answer:

b=136, c=44, d=44

Step-by-step explanation:

B is the same measure as A. C = D and A+B+C+D=360; C+D=88; C=44; D=44

3 0
2 years ago
Cate solved an inequality to find c, the possible number of cats that a shelter can house. She found that c &lt; 28. Which state
stellarik [79]

Since the number of cats has to be less than 28, a statement could be "the shelter can house no more than 28 cats.

5 0
3 years ago
Read 2 more answers
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