Given:
Origin of the clock face (0,0)
label 12 point (0,5)
I am assuming that the radius of the clock is 5 units.
Label 6 should be placed on the point (0,-5). The point of label 12 should be reflected across the x-axis and labeled as 6 of the clock face.
Answer:
Hey mate, here is your answer. Hope it helps you.
Step-by-step explanation:
6x-21 —->
x=21+6
=27
Answer:
0,-4 is the y-intercept and y2+x is the equation I think
Step-by-step explanation:
It is closer to 1. 5/6 is 16 less than 1 and 5/6 is 1/3 more than 1/2, so it would be closer to 1.
