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GREYUIT [131]
3 years ago
12

A corporate team-building event costs $32, plus an additional $1 per attendee. If there are 66 attendees, how much will the corp

orate team-building event cost?
Mathematics
1 answer:
faust18 [17]3 years ago
3 0

Answer:

corporate team-building event cost will cost $98

Step-by-step explanation:

A corporate team-building event costs $32, plus an additional $1 per attendee.

Let cost be C

The expression for the above statement

C($)= 32+n(1)

Where n is the number of attendees

So a situation where there are 66 attendees, the total cost will be

C($) = 32 +66(1)

C($) = 32+66

C($)= 98

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Please help with #12
ExtremeBDS [4]

Answer:

a. 1 1/8 b. 8/9

Step-by-step explanation:

You can set this up as a proportion to solve.  For part a. we know that 2/3 of the road is 3/4 mile long.  2/3 + 1/3 = the whole road, so we need how many miles of the road is 1/3 its length.  Set up the proportion like this:

\frac{\frac{2}{3} }{\frac{3}{4} } =\frac{\frac{1}{3} }{x}

Cross multiplying gives you:

\frac{2}{3}x=\frac{1}{3}*\frac{3}{4}

The 3's on the right cancel out nicely, leaving you with

\frac{2}{3}x=\frac{1}{4}

To solve for x, multiply both sides by 3/2:

\frac{3}{2}*\frac{2}{3}x=\frac{1}{4}*\frac{3}{2} gives you

x=\frac{3}{8}

That means that the road is still missing 3/8 of a mile til it's finished.  The length of the road is found by adding the 3/4 to the 3/8:

\frac{3}{4}+\frac{3}{8}=\frac{6}{8}+\frac{3}{8}=\frac{9}{8}

So the road is a total of 1 1/8 miles long.

For b. we need to find out how much of 1 1/8 is 1 mile:

1 mile = x * 9/8 and

x = 8/9.  When 1 mile of the road is completed, that is 8/9 of the total length of the road completed.

8 0
3 years ago
Find an equation for the nth term of the arithmetic sequence.
amm1812

Answer:

a_n=-301 +37(n-1)

Step-by-step explanation:

arithmetic sequence formula:  a_n=a +(n-1)d

where a is the first term and d is the common difference

Given:

  a_{10}=32

⇒ a +(10-1)d=32

⇒ a+9d=32

Given:

    a_{12}=106

⇒ a +(12-1)d=106

⇒ a+11d=106

Rearrange the first equation to make a the subject:

a = 32 - 9d

Now substitute into the second equation and solve for d

    (32 - 9d) + 11d = 106

⇒ 32 + 2d = 106

⇒ 2d = 106 - 32 = 74

⇒ d = 74 ÷ 2 = 37

Substitute found value of d into the first equation and solve for a:

a + (9 x 37) = 32

a + 333 = 32

a = 32 - 333 = -301

Therefore, the equation is: a_n=-301 +37(n-1)

4 0
2 years ago
A sand dune stands 5 feet above sea level. The hill is eroding at a rate of 1 foot per 20 years. Let y represent the height of t
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y = -1/2x + 5 should be your equation because it is 5 ft above sea level and its eroding, or going down, 1 ft per 20 years. So every year, the sand dune erodes 1/20 ft more.

Hope this helps!
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3 years ago
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