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Akimi4 [234]
2 years ago
6

The price of a man's shirt went from $15 to $20. What was the percent of increase of the price of the shirt? A. 25% A. , 25%, B.

3313% B. , 33 and 1 over 3 percent, C. 20% C. , 20%, D. None of these D. , none of these,
Mathematics
2 answers:
dexar [7]2 years ago
4 0

Answer: 33 1/3%

Step-by-step explanation:

Percentage increase of the shirt will be calculated as:

= Price Increase / Old price × 100%

Price Increase = $20 - $15 = $5

Old price = $15

Percent increase = Price Increase / Old price × 100%

= 5/15 × 100

= 1/3 × 100

= 33 1/3%

Zielflug [23.3K]2 years ago
3 0

Answer:

it would be -25% because 15 is less than 20

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A ship moves through the water at 30 miles/hour at an angle of 30° south of east. The water is moving 5 miles/hour at an angle o
iVinArrow [24]

Answer:

a. 25.98i - 15j mi/h

b. 1.71i + 4.7j mi/h

c. 27.69i -10.3j mi/h

Step-by-step explanation:

a. Identify the ship's vector

Since the ship moves through water at 30 miles per hour at an angle of 30° south of east, which is in the fourth quadrant. So, the x-component of the ship's velocity is v₁ = 30cos30° = 25.98 mi/h and the y-component of the ship's velocity is v₂ = -30sin30° = -15 mi/h

Thus the ship's velocity vector as ship moves through the water v = v₁i + v₂j = 25.98i + (-15)j = 25.98i - 15j mi/h

b. Identify the water current's vector

Also, since the water is moving at 5 miles per hour at an angle of 20° south of east, this implies that it is moving at an angle 90° - 20° = 70° east of north, which is in the first quadrant. So, the x-component of the water's velocity is v₃ = 5cos70° = 1.71 mi/h and the y-component of the water's velocity is v₄ = 5sin70° = 4.7 mi/h

Thus the ship's velocity vector v' = v₃i + v₄j = 1.71i + 4.7j mi/h

c. Identify the vector representing the ship's actual motion.

The velocity vector representing the ship's actual motion is V = velocity vector of ship as ship moves through water + velocity vector of water current.

V = v + v'

= 25.98i - 15j mi/h + 1.71i + 4.7j mi/h

= (25.98i + 1.71i + 4.7j - 15j )mi/h

= 27.68i -10.3j mi/h

7 0
3 years ago
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