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Feliz [49]
3 years ago
15

ASAP will get a thanks

Mathematics
1 answer:
Nataliya [291]3 years ago
7 0
I think it's B Centimeter
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one side of a triangle is half the longest side The third side is 10 feet less than the longest side The perimeter is 70 find al
Ahat [919]

Let the longest side of the triangle be x, then the length of one of the other sides of the triangle is 0.5x and the length of the third side is x - 10.

Then, x + 0.5x + x - 10 = 70

2.5x = 80

x = 80 / 2.5 = 32

Therefore, the length of the sides of the triangle are: 32, 0.5(32) = 16 and 32 - 10 = 22.

i.e. 32, 16, 22

8 0
3 years ago
Identify the horizontal asymptote of each graph​
Roman55 [17]

Answer:A: y=0

Step-by-step explanation:

Edge

3 0
3 years ago
At Hogwarts School of Witchcraft and Wizardry, the Sorting Hat chooses one of four houses for each first-year student. If 4 stud
weeeeeb [17]

Answer:

Probability that they are the youngest is 0.000549

Step-by-step explanation:

Given

Number of students = 16

Selected students = 4

Let n = number of students

n = 16

Let r = selections

r = 4

We're interested in selecting 4 students out of 16; the keyword, selection means we're dealing with combination because order is not important.

So,

Solving for nCr

nCr = n!/((n-r)!r!)

16C4 = 16!/((16-4)!4!)

16C4 = 16!/(12!4!)

16C4 = 16 * 15 * 14 * 13 * 12!/(12!4!)

16C4 = 16 * 15 * 14 * 13 / 4 * 3 * 2 * 1

16C4 = 1820 ways

There are 1820 ways of selecting 4 students from a total of 1820.

Only one of these ways can the four of them be the youngest.

So, probability = 1/1820

Probability = 0.0005494506

Probability that they are the youngest is 0.000549 (approximately)

3 0
3 years ago
Solve for a side in a right triangle
sergeinik [125]

Answer:

1.88 = ?

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

cos theta = adjacent / hypotenuse

cos 20 = ?/ 2

Multiply each side by 2

2 cos 20 = ?

1.879385242 = ?

To the nearest hundredth

1.88 = ?

3 0
3 years ago
Self publishing problem
dem82 [27]

Answer:

1) Expense. As an independent author, the issue of what to spend on my books is something I battle with constantly. ...

Solution. ...

2) Audience. ...

Solution. ...

3) Reviews. ...

Solution. ...

4) Self-publishing itself. ...

Solution.

8 0
2 years ago
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