Let the longest side of the triangle be x, then the length of one of the other sides of the triangle is 0.5x and the length of the third side is x - 10.
Then, x + 0.5x + x - 10 = 70
2.5x = 80
x = 80 / 2.5 = 32
Therefore, the length of the sides of the triangle are: 32, 0.5(32) = 16 and 32 - 10 = 22.
i.e. 32, 16, 22
Answer:A: y=0
Step-by-step explanation:
Edge
Answer:
Probability that they are the youngest is 0.000549
Step-by-step explanation:
Given
Number of students = 16
Selected students = 4
Let n = number of students
n = 16
Let r = selections
r = 4
We're interested in selecting 4 students out of 16; the keyword, selection means we're dealing with combination because order is not important.
So,
Solving for nCr
nCr = n!/((n-r)!r!)
16C4 = 16!/((16-4)!4!)
16C4 = 16!/(12!4!)
16C4 = 16 * 15 * 14 * 13 * 12!/(12!4!)
16C4 = 16 * 15 * 14 * 13 / 4 * 3 * 2 * 1
16C4 = 1820 ways
There are 1820 ways of selecting 4 students from a total of 1820.
Only one of these ways can the four of them be the youngest.
So, probability = 1/1820
Probability = 0.0005494506
Probability that they are the youngest is 0.000549 (approximately)
Answer:
1.88 = ?
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
cos theta = adjacent / hypotenuse
cos 20 = ?/ 2
Multiply each side by 2
2 cos 20 = ?
1.879385242 = ?
To the nearest hundredth
1.88 = ?
Answer:
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