It's D, it's the only one where it has a -6 at the end other than A, but if you look at the A when distributed there isn't a 23x<span />
Answer: 33
Step-by-step explanation:
Input the numbers into the variables.
7(2) + 3 + 16
14 + 3 + 16
17 + 16
33
#5
57.8 can be rounded to 60 because 57.8 is closer to 60 than 50 and 81 is relatively close to 80. if we had to estimate the quotient, we would have
60 ÷ 80 = 0.75
#8
2.8 can be rounded to 3 because 2.8 is closer to 3 than it is to 2 and 6 can be left alone because it will make our division easier.
3 ÷ 6 = 0.5
#11
737.5 can be rounded to 700 and 9 can be rounded to 10.
700 ÷ 10 = 100
To evaluate the probability that the lifespan will be between 1440 and 1465 hours will be given by:
P(1440<x<1465)
using the z-score formula we obtain:
z=(x-μ)/σ
where:
μ=1450
σ=8.5
hence
when x=1440
z=(1440-1450)/8.5
z=-1.18
P(z<-1.18)=0.1190
when x=1465
z=(1465-1450)/8.5
z=1.77
P(z<1.77)=0.9625
hence:
P(1440<x<1465)
=0.9625-0.1180
=0.8445
The histogram is attached. Every column shows on the bottom the range of age and on the left the number of cars of that particular age.
In order to find the percentage of cars with less than 20 years or more than 40 years, you have to sum up the numbers of cars in the first two columns from left (age 0-9 and 10-19) and the last two (age 40-49 and 50-59).
The number of cars of requested age is: 3 + 2 + 0 + 3 = 8
Now, you need to calculate the total number of cars (sum the cars of every column): 3 + 2 + 8 + 4 + 0 + 3 = 20
Lastly, you need to calculate the ration between the cars of requested age and the total number of cars, and transform it into a percentage:
8 ÷ 20 = 0.40 = 40%
Therefore, your answer is
40%.