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ale4655 [162]
3 years ago
14

Can someone help me please!!!

Mathematics
1 answer:
Andre45 [30]3 years ago
6 0

Answer: 3

<u>Explanation:</u>

Since we want the least number of integers, divide by the largest integer (9).

2018 ÷ 9 = 224 remainder 2

So, N = 2999...999 <em>(there are 224 of the 9's) </em>

Thus, N + 1 = 2999...999 + 1 <em>(there are 224 of the 9's) </em>

<em>                   </em>= 3000...000     <em>(there are 224 of the 0's) </em>

The sum of the digits is: 3 + 0 + ... + 0  <em>(there are 224 of the 0's) </em>

                                      = 3

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$33.33

Step-by-step explanation:

Use the formula i = prt, where p is the principal, r is the interest rate as a decimal fraction and t is the elapsed time in years.

Here, i = $500*(0.10)*(2/3 year) = $33.33

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In the past ten years, the population of a city decreased from 90,000 to 75,000 Find the percent decrease.
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The mean amount spent by a family of four on food per month is $500 with a standard deviation of $75. Assuming that the food cos
JulijaS [17]

Answer:

The probability that a family spends less than $410 per month

P( X < 410) = 0.1151

Step-by-step explanation:

<u><em>Step(i):-</em></u>

<em>Given mean of the population = 500 </em>

<em>Given standard deviation of the Population = 75</em>

Let 'X' be the variable in normal distribution

      Z = \frac{x-mean}{S.D}

<em>Given X = $410</em>

<em></em>Z = \frac{410-500}{75} = - 1.2<em></em>

<u><em>Step(ii):-</em></u>

The probability that a family spends less than $410 per month

P( X < 410) = P( Z < - 1.2 )

                  =  0.5 - A( -1.2)

                 = 0.5 - A(1.2)

                = 0.5 - 0.3849  ( ∵from normal table)

                = 0.1151

<u>Final answer:-</u>

The probability that a family spends less than $410 per month

P( X < 410) = 0.1151

6 0
3 years ago
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