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ale4655 [162]
3 years ago
14

Can someone help me please!!!

Mathematics
1 answer:
Andre45 [30]3 years ago
6 0

Answer: 3

<u>Explanation:</u>

Since we want the least number of integers, divide by the largest integer (9).

2018 ÷ 9 = 224 remainder 2

So, N = 2999...999 <em>(there are 224 of the 9's) </em>

Thus, N + 1 = 2999...999 + 1 <em>(there are 224 of the 9's) </em>

<em>                   </em>= 3000...000     <em>(there are 224 of the 0's) </em>

The sum of the digits is: 3 + 0 + ... + 0  <em>(there are 224 of the 0's) </em>

                                      = 3

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A survey was conducted to determine the average age at which college seniors hope to retire in a simple random sample of 101 sen
tatyana61 [14]

Answer:

96% confidence interval for desired retirement age of all college students is [54.30 , 55.70].

Step-by-step explanation:

We are given that a survey was conducted to determine the average age at which college seniors hope to retire in a simple random sample of 101 seniors, 55 was the  average desired retirement age, with a standard deviation of 3.4 years.

Firstly, the Pivotal quantity for 96% confidence interval for the population mean is given by;

                         P.Q. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample average desired retirement age = 55 years

            \sigma = sample standard deviation = 3.4 years

            n = sample of seniors = 101

            \mu = true mean retirement age of all college students

<em>Here for constructing 96% confidence interval we have used One-sample t test statistics as we don't know about population standard deviation.</em>

<u>So, 96% confidence interval for the population mean, </u>\mu<u> is ;</u>

P(-2.114 < t_1_0_0 < 2.114) = 0.96  {As the critical value of t at 100 degree

                                               of freedom are -2.114 & 2.114 with P = 2%}  

P(-2.114 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.114) = 0.96

P( -2.114 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 2.114 \times {\frac{s}{\sqrt{n} } } ) = 0.96

P( \bar X-2.114 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.114 \times {\frac{s}{\sqrt{n} } } ) = 0.96

<u>96% confidence interval for</u> \mu = [ \bar X-2.114 \times {\frac{s}{\sqrt{n} } } , \bar X+2.114 \times {\frac{s}{\sqrt{n} } } ]

                                           = [ 55-2.114 \times {\frac{3.4}{\sqrt{101} } } , 55+2.114 \times {\frac{3.4}{\sqrt{101} } } ]

                                           = [54.30 , 55.70]

Therefore, 96% confidence interval for desired retirement age of all college students is [54.30 , 55.70].

7 0
3 years ago
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Nataly_w [17]

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Step-by-step explanation:

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Answer:

B. 10

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Step-by-step explanation:

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Distribute the numbers similarly to the example before:

12p - 6 = -6 + 12p

Subtract '12p' from both sides:

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Add '6' to both sides:

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Ms. Jan brought in cookies for her class. She gave out half of them in the morning. At lunch, she gave out 12 more. She then had
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Answer:

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