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3 years ago

What's three equivalent ratios for 6/9

Mathematics

2 answers:

Andreas93 [3]3 years ago

7 0

2/3 12/18 24/36

Hhhhhhhhhhhhhhh

vaieri [72.5K]3 years ago

4 0

Answer:

Three equivalents ratios for 6/9 could be 2/3, 12/18 and 18/27

Step-by-step explanation:

An equivalent ratio refers to the same number but written differently. For example, for the ratio 6/9, we could obtain the following equivalent ratios.

First equivalent ratio

You can divide the numerator and denominator by 3. You get 2/3

$\frac{6\div 3}{9\div 3}=\frac{2}{3}$

Second equivalent ratio

You can multiply the numerator and denominator by 2. You get 12/18

$\frac{6\times 2}{9\times 2}=\frac{12}{18}$

Third equivalent ratio

You can multiply the numerator and denominator by 3. You get 18/27

$\frac{6\times 3}{9\times 3}=\frac{18}{27}$

Thus, three equivalents ratios for 6/9 could be 2/3, 12/18 and 18/27

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If anyone knows about definite integrals for calculus then please I request help! I

kicyunya [14]

Answer:

$\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{1}{8} \bigg( e^\Big{\frac{4}{25}} - e^\Big{\frac{4}{81}} \bigg)$

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Integration

Integrals

Integration Rule [Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)$

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

U-Substitution

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx$

Step 2: Integrate Pt. 1

Identify variables for u-substitution.

Set u: $\displaystyle u = 4x^{-2}$
[u] Differentiate [Basic Power Rule, Derivative Properties]: $\displaystyle du = \frac{-8}{x^3} \ dx$
[Bounds] Switch: $\displaystyle \left \{ {{x = 9 ,\ u = 4(9)^{-2} = \frac{4}{81}} \atop {x = 5 ,\ u = 4(5)^{-2} = \frac{4}{25}}} \right.$

Step 3: Integrate Pt. 2

[Integral] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}\int\limits^9_5 {\frac{-8}{x^3}e^\big{4x^{-2}}} \, dx$
[Integral] U-Substitution: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}\int\limits^{\frac{4}{81}}_{\frac{4}{25}} {e^\big{u}} \, du$
[Integral] Exponential Integration: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}(e^\big{u}) \bigg| \limits^{\frac{4}{81}}_{\frac{4}{25}}$
Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8} \bigg( e^\Big{\frac{4}{81}} - e^\Big{\frac{4}{25}} \bigg)$
Simplify: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{1}{8} \bigg( e^\Big{\frac{4}{25}} - e^\Big{\frac{4}{81}} \bigg)$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

4 0

2 years ago

Is -8 - 2(3+2n)+7n equivalent to -30 - 13n

soldi70 [24.7K]

Answer:

The terms are not equivalent

Step-by-step explanation:

-8 - 2(3+2n)+7n

Distribute the 2

-8 -6-4n+7n

Combine like terms

-14 +3n

That is not equal to -30 -13n

The terms are not equivalent

4 0

3 years ago

A box contains different colored paper clips. The probability of drawing two red paper clips from the box without replacement is

ivann1987 [24]

Answer: 5/14 which is choice B

================================================

How I got this answer:

Define the following events

A = event of picking a red paper clip on the first selection

B = event of picking a red paper clip on the second drawing

Replacement is not made.

Now onto the probabilities for each

P(A) = 2/5 = 0.4 is given to us as this is simply the probability of picking red on the first try

P(A and B) = probability of both events A and B happeing simultaneously = 1/7

P(B|A) = probability event B occurs, given event A has occured

P(B|A) = probability of selecting red on second selection, given first selection is red (no replacement)

P(B|A) = P(A and B)/P(A)

P(B|A) = (1/7) / (2/5)

P(B|A) = (1/7) * (5/2)

P(B|A) = (1*5)/(7*2)

P(B|A) = 5/14

So if event A happens, then the chances of event B happening is 5/14

------------------

A more concrete example:

If we had 15 paperclips, and 6 of them were red, then

P(A) = (# of red)/(# total) = 6/15 = 2/5

P(B|A) = (# of red left)/(# total left) = (6-1)/(15-1) = 5/14

P(A and B) = P(A)*P(B|A) = (2/5)*(5/14) = 10/70 = 1/7

7 0

3 years ago

Read 2 more answers

Intermediate algebra. please help to solve

BARSIC [14]

7x = -36+10x

X=12
You minus the 10 from 7 (7-10=-3) (-36/-3) gives you 12

6 0

3 years ago

Determine if the side lengths 6, 11, and 19 form a triangle. If it is a triangle, classify it by its sides.

Butoxors [25]

It is not triangle because the one side of triangle should be smaller than the other two sides
Let's check
6+11=17
17<19
Or
11+19=31
9<31

4 0

3 years ago