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kari74 [83]
2 years ago
8

Urgent help wanted/ needed

Mathematics
1 answer:
konstantin123 [22]2 years ago
6 0

The equation in slope-intercept form is: y = -x + 5

The equation in point-slope form is: y - 3 = -1(x - 2)

<h3>How to Find the Equation of a Line in Point-Slope Form and Slope-intercept Form?</h3>
  • Where (a, b) is a point on the line and m is the slope of the line, the equation in point-slope form for such line would be: y - b = m(x - a).
  • Where b = y-intercept and m = slope, the slope-intercept form for the equation of the line is expressed as: y = mx + b.

Slope (m) = rise/run = -(2/2) = -1

Y-intercept (b) = 5 (where the line intercepts the y-axis)

Using a point, (2, 3) = (a, b) and m = -1, the equation in point-slope form is:

y - 3 = -1(x - 2)

Rewrite in slope-intercept form:

y - 3 = -x + 2

y = -x + 2 + 3

y = -x + 5

Learn more about point-slope and slope-intercept form on:

brainly.com/question/24907633

#SPJ1

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Answer:

x= 2

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Step-by-step explanation:

<u>Solving as normal quadratic equation:</u>

  • 2x^2+2x=12
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<u>Roots are</u> 2 and -3

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