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lesya [120]
3 years ago
12

A figure in the second quadrant is reflected over the y-axis. In which quadrant will the reflected figure appear?

Mathematics
1 answer:
alukav5142 [94]3 years ago
3 0

It would be in the first quadrant since the second quadrant is on the other side of the y-axis.


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statuscvo [17]
Formula for finding the area of a rectangle: length x width

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3 years ago
Solve 2(4/x+8)=18 <br><br> Side note: 4/X is supposed to be a fraction
kirill115 [55]

9514 1404 393

Answer:

  x = 4

Step-by-step explanation:

Divide by 2, subtract 8 ...

  2(4/x +8) = 18

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  4 = x . . . . . multiply by x

6 0
2 years ago
Read 2 more answers
1. What is the value of h? (1 point)
irinina [24]

The value of h is 11.3.

Solution:

Given data:

The triangle is a right triangle.

θ = 45° and opposite side of θ = 8

The value of sin 45° = \frac{1}{\sqrt{2} }

Using trigonometric formula,

$\sin\theta=\frac{\text{Opposite side}}{\text{Hypotenuse}}

$\sin45^\circ=\frac{{8}}{h}

$\frac{1}{\sqrt{2} } =\frac{{8}}{h}

Do cross multiplication.

h = 8\sqrt 2

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The value of h is 11.3.

7 0
3 years ago
What is the length of BC ?<br>​
galben [10]
The answer is c.

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7 0
2 years ago
Read 2 more answers
If 8 identical blackboards are to be divided among 4 schools,how many divisions are possible? How many, if each school mustrecei
MAXImum [283]

Answer:

There are 165 ways to distribute the blackboards between the schools. If at least 1 blackboard goes to each school, then we only have 35 ways.

Step-by-step explanation:

Essentially, this is a problem of balls and sticks. The 8 identical blackboards can be represented as 8 balls, and you assign them to each school by using 3 sticks. Basically each school receives an amount of blackboards equivalent to the amount of balls between 2 sticks: The first school gets all the balls before the first stick, the second school gets all the balls between stick 1 and stick 2, the third school gets the balls between sticks 2 and 3 and the last school gets all remaining balls.

 The problem reduces to take 11 consecutive spots which we will use to localize the balls and the sticks and select 3 places to put the sticks. The amount of ways to do this is {11 \choose 3} = 165 . As a result, we have 165 ways to distribute the blackboards.

If each school needs at least 1 blackboard you can give 1 blackbooard to each of them first and distribute the remaining 4 the same way we did before. This time there will be 4 balls and 3 sticks, so we have to put 3 sticks in 7 spaces (if a school takes what it is between 2 sticks that doesnt have balls between, then that school only gets the first blackboard we assigned to it previously). The amount of ways to localize the sticks is {7 \choose 3} = 35. Thus, there are only 35 ways to distribute the blackboards in this case.

4 0
3 years ago
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