Answer:
1) True
2) True
3) False
4) True
Step-by-step explanation:
1) You can compare irrational numbers using rational approximations
The above statement is true as given two irrational numbers which can be expressed in decimal format, by rounding up the numbers to a certain number of decimal places, the values of the irrational numbers will be different
2) Square roots can be compared and ordered by comparing and ordering the numbers underneath the radical symbol
The above statement is true as the the values of the numbers under the radical symbol are directly proportional to the square root
3) You cannot compare the value of rational and irrational numbers
The above statement is false because the value of an irrational number can be found between two rational numbers. Therefore, the value of an irrational number is higher than the rational number that precedes it on the left of a number line
4) The closer the numbers being compared, the more decimal places you need to use
The above statement is true as a higher level of detailed value of the numbers being compared will be required given the closeness in value of the numbers being compared.
Answer:
The relationship ⇒ <u>25x + 40y = 12,250</u>
Step-by-step explanation:
The number of student memberships = x
The number of adult memberships = y
The monthly membership fee for a student = $25
The monthly membership fee for an adult = $40
The total fee = 25x + 40y
Al's Athletic Club receives $12,250 in membership fees for the month of January.
So, the relationship between x and y is:
<u>25x + 40y = 12,250</u>
It's sometimes true.
One example is the least common multiple of 2 and 3 is 6, which is their product.
But the product isn't always the answer because (example 2:) the least common multiple of 6 and 10 is 30 because 6*5=30 and 3*10=30, however 6*10 is 60.
Ergo, it is only sometimes true.
Answer: Number one would be 3x+2y+-14 and x+y=-4, second one is x=-3, y=7
Step-by-step explanation:
The first one is solved by inputting the x and y in each one and finding which one comes out true, the second on is solved by substitution. to find x you would subtract x in the first equation and make it y=4-x then input that equation in the y in the second equation.
Answer:
D = 4, Z = 24
Step-by-step explanation:
6D+3Z = 96
5D+4Z = 116
multiply top by 5 and bottom by -6
top equation = 30D+15Z = 480
bottom equation = -30D-24Z = -696
Cancel 30D and -30 D
top equation = 15Z = 480
Bottom equation = -24Z = -696
15Z - 24 Z = 480 - 696
-9Z = 216
Z = 216/9
Z = 24
Now that we have the value of Z, we can substitute it in any equation to find D
6D + 3(24) = 96
6D + 72 = 96
6D = 96 - 72
6D = 24
D = 24/6
D = 4
