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denis23 [38]
2 years ago
5

You want to calculate the value of your car each year when it depreciates by 15%. What does the term y mean in the exponential f

unction y=9500*0.85^x?

Mathematics
2 answers:
insens350 [35]2 years ago
4 0

Answer:

Value of the car after x years

Step-by-step explanation:

Exponential functions are generally expressed in the form: y=a(b)^x and since this function is decreasing, meaning it has an exponential decay, it can be expressed as: y=a(1-r)^x where r=rate of decay.

In this case the a represents the initial value or y-intercept, since when x=0, (1-r)^0 = 1, so we just have y=a(1) or y=a

The r represents the rate of decay

the x usually represents the time in seconds, days, months, or whatever unit is being used

The y value represents the value of whatever your measuring, and in this context it represents the value of the car after x years.

This is because a represents the initial value

After one year it's only 85% worth it's initial value or 15% less which is represented as 0.85(a)

After two years it's only 85% worth the previous year or 15% less the previous year, which is represented as 0.85(0.85(a))

This will continue to decrease the number of years increase

Alex73 [517]2 years ago
4 0

Answer:

the value of your car after x years

Step-by-step explanation:

The given function represents a geometric sequence with initial term $9500 and common factor 0.85.  Note that every time x increases by 1, we get the newest term by multiplying the previous one by 0.85.  The given function y=9500*0.85^x represents the value of your car after x years (which matches the 3rd answer choice).

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Sergeu [11.5K]
0x=2x+3, it would = 3/2
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3 years ago
I’ll put you as brainliest
kari74 [83]

The law of an object moving with constant acceleration is

s(t)=s_0+v_0t+\dfrac{1}{2}at^2

Where s is space, t is time, s_0 is the initial position, v_0 is the initial velocity and a is the acceleration.

In this case, if we choose a reference grid with the vertical axis pointing upwards, the acceleration of gravity will point downwards (and thus be negative). The initial position is zero, because the rocket is on the ground, and the initial velocity is 100 (positive because pointing upwards).

So, its law is

h(t)=100t-\dfrac{1}{2}gt^2

(I changed s for h since the rocket is moving vertically, so its position is actually its height. Also, g is the acceleration due to gravity).

The rocket hits the ground if its height is zero, so if we set h=0 we have

0=100t-\dfrac{1}{2}gt^2 \iff t(100-\dfrac{1}{2}gt)=0

Solving for t, we have either t=0, or

100-\dfrac{1}{2}gt=0 \iff 100=\dfrac{1}{2}gt \iff 200=gt \iff t=\dfrac{200}{g}

The solution t=0 means that at the beginning the rocket is on the ground. So, we're interested in the other solution. Considering that g is about 32.2 feet/s^2, we have

t=\dfrac{200}{g}\approx \dfrac{200}{32.2}\approx 6.21

3 0
3 years ago
Find the length of side x simplest radical form with a rational denominator
Nuetrik [128]

Answer:

The length of x in the simplest radical form with a rational denominator will be:      

  •       x=\frac{5\sqrt{3}}{2}

Step-by-step explanation:

Given

hypotenuse = 5

angle Ф = 60°

To determine

x = ?

Using the trigonometric ratio

cos Ф = adjacent / hypotenuse

here

Ф = 60°

adjacent of 60° = x

hypotenuse = 5

so substituting Ф = 60°, adjacent = x and hypotenuse = 5 in the equation

cos Ф = adjacent / hypotenuse

so

cos\:60^{\circ }\:=\:\frac{x}{5}

       \frac{\sqrt{3}}{2}=\frac{x}{5}

switch sides

         \frac{x}{5}=\frac{\sqrt{3}}{2}

Multiply both sides by 5

         \frac{5x}{5}=\frac{5\sqrt{3}}{2}

Simplify

         x=\frac{5\sqrt{3}}{2}

Therefore, the length of x in the simplest radical form with a rational denominator will be:      

  •       x=\frac{5\sqrt{3}}{2}
5 0
3 years ago
Help please!!!!!!!I don’t know this! Tyy
aleksley [76]
<h3>Answer: Choice C.  4*sqrt(6)</h3>

====================================================

Explanation:

Each cube has a side length of 4. Placed together like this, the total horizontal side combines to 4+8 = 8. This is the segment HP as shown in the diagram below. I've also added point Q to form triangle HPQ. This is a right triangle so we can find the hypotenuse QH

Use the pythagorean theorem to find QH

a^2 + b^2 = c^2

(HP)^2 + (PQ)^2 = (QH)^2

8^2 + 4^2 = (QH)^2

(QH)^2 = 64 + 16

(QH)^2 = 80

QH = sqrt(80)

Now we use segment QH to find the length of segment EH. Focus on triangle HQE, which is also a right triangle (right angle at point Q). Use the pythagorean theorem again

a^2 + b^2 = c^2

(QH)^2 + (QE)^2 = (EH)^2

(EH)^2 = (QH)^2 + (QE)^2

(EH)^2 = (sqrt(80))^2 + (4)^2

(EH)^2 = 80 + 16

(EH)^2 = 96

EH = sqrt(96)

EH = sqrt(16*6)

EH = sqrt(16)*sqrt(6)

EH = 4*sqrt(6), showing the answer is choice C

-------------------------

A shortcut is to use the space diagonal formula. As the name suggests, a space diagonal is one that goes through the solid space (rather than stay entirely on a single face; which you could possibly refer to as a planar diagonal or face diagonal).

The space diagonal formula is

d = sqrt(a^2+b^2+c^2)

which is effectively the 3D version of the pythagorean theorem, or a variant of such.

We have a = HP = 8, b = PQ = 4, and c = QE = 4 which leads to...

d = sqrt(a^2+b^2+c^2)

d = sqrt(8^2+4^2+4^2)

d = sqrt(96)

d = sqrt(16*6)

d = sqrt(16)*sqrt(6)

d = 4*sqrt(6), we get the same answer as before

The space diagonal formula being "pythagorean" in nature isn't a coincidence. Repeated uses of the pythagorean theorem is exactly why this is.

4 0
3 years ago
-8&lt;2x-4&lt;4 solve the inequality
il63 [147K]

Answer:

Step-by-step explanation:

The inequality will be split into two

It is know that, if a<b<c

Then a<b and b<c

-8<2x-4<4

Apply that to this

Then,

-8<2x-4. Equation 1

Also,

2x-4<4 equation 2

Solving equation 1

-8<2x-4

Add 4 to both side of the equation

-8+4<2x-4+4

-4<2x

Divide both sides by 2

-4/2<2x/2

-2<x

Note, if a is less than b, then, b is greater than a, e.g. 4 is less than 10, this implies 10 is greater than 4

Therefore,

-2<x

Then, x greater than -2

Equation 2

2x-4<4

Add 4 to both side of the inequalities

2x-4+4<4+4

2x<8

Divide both side by 2

Then,

2x/2<8/2

x<4

Therefore x is between -2 and +4.

Check attachment for graphical solution

7 0
3 years ago
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