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maksim [4K]
3 years ago
9

Please help thanks!

Mathematics
1 answer:
Kryger [21]3 years ago
4 0

Answer:

All except irrational-

Step-by-step explanation:

100/100 is 1. This makes it real, an integer, whole,natural, and rational.

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In a class, 60% of the students are boys and the rest are girls. If the number of boys is 30, how many students are there? ​
irga5000 [103]

50 total students

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Explanation:

total students: 100%

----------------

  • 60% → 30
  • 1% → 30/60
  • 1% → 0.5
  • 100% → (0.5 * 100)
  • 100% → 50

number of girls:

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2 years ago
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mafiozo [28]

Answer:

correct answer

Step-by-step explanation:

250/6=125/3=41.67

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3 years ago
The total monthly profit for a firm is P(x)=6400x−18x^2− (1/3)x^3−40000 dollars, where x is the number of units sold. A maximum
wlad13 [49]

Answer:

Maximum profits are earned when x = 64 that is when 64 units are sold.

Maximum Profit = P(64) = 2,08,490.666667$

Step-by-step explanation:

We are given the following information:P(x) = 6400x - 18x^2 - \frac{x^3}{3} - 40000, where P(x) is the profit function.

We will use double derivative test to find maximum profit.

Differentiating P(x) with respect to x and equating to zero, we get,

\displaystyle\frac{d(P(x))}{dx} = 6400 - 36x - x^2

Equating it to zero we get,

x^2 + 36x - 6400 = 0

We use the quadratic formula to find the values of x:

x = \displaystyle\frac{-b \pm \sqrt{b^2 - 4ac} }{2a}, where a, b and c are coefficients of x^2, x^1 , x^0 respectively.

Putting these value we get x = -100, 64

Now, again differentiating

\displaystyle\frac{d^2(P(x))}{dx^2} = -36 - 2x

At x = 64,  \displaystyle\frac{d^2(P(x))}{dx^2} < 0

Hence, maxima occurs at x = 64.

Therefore, maximum profits are earned when x = 64 that is when 64 units are sold.

Maximum Profit = P(64) = 2,08,490.666667$

6 0
3 years ago
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Rainbow [258]

Answer:

g=18

Step-by-step explanation:

Isolate the variables by dividing each side by -2.5.

5 0
3 years ago
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