Answer:
Step-by-step explanation:
H(3,2) & J(4, 1)
K(-2,-4) & M(-1 , -5)
![Slope =\dfrac{-5-[-4]}{-1-[-2]}\\\\=\dfrac{-5+4}{-1+2}\\\\= \dfrac{-1}{1}\\\\\\= -1](https://tex.z-dn.net/?f=Slope%20%3D%5Cdfrac%7B-5-%5B-4%5D%7D%7B-1-%5B-2%5D%7D%5C%5C%5C%5C%3D%5Cdfrac%7B-5%2B4%7D%7B-1%2B2%7D%5C%5C%5C%5C%3D%20%5Cdfrac%7B-1%7D%7B1%7D%5C%5C%5C%5C%5C%5C%3D%20-1)
Line HJ and KM have same slopes. So, they are parallel
The answer is no because the problem has no solution. Hope this helps
The width : the length
= 48mm : 105mm
=16 : 35
Answer:
Step-by-step explanation:
y = -4x + 6.....switch x and y and solve for y
x = -4y + 6 ....subtract 6 from both sides
x - 6 = -4y....divide by -4 on both sides
(x - 6) / -4 = y or y = -1/4x + 3/2 <====
Answer:
This is the “best” method whenever the quadratic equation only contains x2 terms.
The general approach is to collect all x2 terms on one side of the equation while keeping the constants to the opposite side.
step by step: but in order to solve a quadratic using the square root principle the problem must be in the correct form. To solve a quadratic using the square root principle the quadratic must be in vertex form, a(x – h)2 + k.
