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4 years ago

actor x3 + x2 + x + 1 by grouping. What is the resulting expression? (x2)(x + 1) (x2 + 1)(x) (x2 + 1)(x + 1) (x3 + 1)(x + 1)

1 answer:

5 0

So for this, factor x^3 + x^2 and x + 1 separately. Make sure that they have the same quantity on the inside: $x^2(x+1)+1(x+1)$

Now you can rewrite the expression as: $(x^2+1)(x+1)$ , which is your final answer.

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Please help compare these integers by typing the symbol that would make the statement true

faust18 [17]

>
Positive integers are always greater.

3 0

4 years ago

Evaluate f(x)=x+3for f(-2)

nirvana33 [79]

Answer:

f(-2) = 1.

Step-by-step explanation:

If we are solving for f(-2), we will simply need to substitute in '-2' for 'x'. This gives us:

f(-2) = -2 + 3

f(-2) = 1.

4 0

3 years ago

Read 2 more answers

Consider this scenario: The population of a city increased steadily over a ten-year span. The following ordered pairs show the p

vova2212 [387]

Answer:

Regression function: $y=1986.406+0.0059x$

The function predicts that population will reach 14,000 in year 2068.

Step-by-step explanation:

We have to determine a function $y=b_0+b_1x_1$ by applying linear regression. The data we have is 5 pair of points which relates population to year.

According to the simple regression model (one independent variable), if we minimize the error between the model (the linear function) and the points given, the parameters are:

$b_0=\bar{y}+b_1\bar{x}\\\\b_1=\frac{\sum\limits^5_{i=1} {(x_i-\bar x)(y_i-\bar y)}}{\sum\limits^5_{i=1} {(x_i-\bar x)^2}}$

We start calculating the average of x and y

$\bar x=\frac{2500+2650+3000+3500+4200}{5}=\frac{15850}{5}=3170\\\\ \bar y=\frac{2001+2002+2004+2007+2011}{5}=\frac{10025}{5}=2005$

The sample covariance can be calculated as

$\sum\limits^5_{i=1} {(x_i-\bar x)(y_i-\bar y)}=(2500-3170)(2001-2005)+(2650-3170)(2002-2005)+(3000-3170)(2004-2005)+(3500-3170)(2007-2005)+(4200-3170)(2011-2005)\\\\\sum\limits^5_{i=1} {(x_i-\bar x)(y_i-\bar y)}=2680+1560+170+660+6180\\\\ \sum\limits^5_{i=1} {(x_i-\bar x)(y_i-\bar y)}=11250$

The variance of x can be calculated as

$\sum\limits^5_{i=1} {(x_i-\bar x)^2}=(2500-3170)^2+(2650-3170)^2+(3000-3170)^2+(3500-3170)^2+(4200-3170)^2\\\\\sum\limits^5_{i=1} {(x_i-\bar x)^2}=448900+270400+28900+108900+1060900\\\\\sum\limits^5_{i=1} {(x_i-\bar x)^2}=1918000$

Now we can calculate the parameters of the regression model

$b_1=\frac{\sum\limits^5_{i=1} {(x_i-\bar x)(y_i-\bar y)}}{\sum\limits^5_{i=1} {(x_i-\bar x)^2}}=\frac{11250}{1918000}=0.005865485 \\\\ b_0=\bar{y}+b_1\bar{x}=2005-0.005865485*3170=1986.406413$

The function then become:

$y=1986.406+0.0059x$

With this linear equation we can predict when the population will reach 14,000:

$y=1986.406+0.0059(14,000)=1986.406+82.117=2068.523$

6 0

3 years ago

(7y - 2n) - (5y + 3a) =<br><br> Pls help

Sati [7]

Answer:

2y-2n-3a

Step-by-step explanation:

(7y-2n) - (5y+3a)

7y-2n-5y-3a

2y-2n-3a

4 0

3 years ago

Read 2 more answers

If 5<2x+3<11, what is the possible range of value of -4x-6

Lady bird [3.3K]

Answer:

-10 > (-4x - 6) > -22

Step-by-step explanation:

Given inequality is 5 < 2x + 3 < 11

Now we will multiply this inequality by (-2) resulting,

5(-2) > (2x + 3)(-2) > 11(-2)

-10 > (-4x - 6) > -22 (Sign of inequality gets reversed when the inequality is multiplied or divided by a negative number)

Therefore, the possible range of (-4x - 6) is between -22 and -10.

4 0

4 years ago