Answer:
d) 0.4
Step-by-step explanation:
P(Ra) = 0.998
P(Rb) = 0.995
P(A) = 0.4
P(B) = 0.6
The probability that method A was performed, given that the eye was recovered within a month of the surgery, is determined by the probability that the eye recovered within a month with method A (P(A) x P(Ra)),divided by the probability that the eye recovered within a month with either method (P(A) x P(Ra) + P(B) x P(Rb)):
The probability that method A was performed is 0.40.
9/10×4=36/10 or 3 3/5. As a result, they have used 3 3/5 boxes of paper in 4 days. Hope it help!
Answer:
109
Step-by-step explanation:
You can brute-force this:
Candidate numbers that are divisable by 13 if you take away 5: 18
, 31
, 44
, 57
, 70
, 83
, 96
, <u>109
</u>, 122
, 135
, 148
Candidate numbers that are divisable by 14 if you take away 11: 25
, 39
, 53
, 67
, 81
, 95
, <u>109
</u>, 123
, 137
Only 109 is in both lists.
Step-by-step explanation:
Factors of 21 are 1, 3, 7 and 21.
a + f + t cannot be 1 or 3 as it cannot be written as a sum of 3 distinct digits, so it is 7.
The smallest 3 remaining digits are 2, 5 and 6 which add to 13.
So there are no solutions.