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serg [7]
2 years ago
12

I will give brainly but please show how you got the answer when you answer the questions

Mathematics
1 answer:
Angelina_Jolie [31]2 years ago
3 0

Answer: point C = (3.75, 1.5)

Step-by-step explanation:

As the direction of the distance is from A to B, we need to down the y-axis and along (to the right) the x-axis.

Find the distance between the x-coordinates of both points by subtracting the x-coordinate of A from the x-coordinate of B:

5 - 0 = 5

3/4 of the length of this distance = 0.75 x 5 = 3.75

So the x-coordinate of C will be the sum of the distance (3.75) and the x-coordinate of A (as we are "travelling" from A to B):

3.75 + 0 = 3.75

Find the distance between the y-coordinates of both points by subtracting the y-coordinate of B from the y-coordinate of A:

3 - 1 = 2

3/4 of the length of this distance = 0.75 x 2 = 1.5

So the y-coordinate of C will be the y-coordinate of A minus the distance (1.5):

3 - 1.5 = 1.5

Therefore, point C = (3.75, 1.5)

Hope that helps - i dont know what u meant by option 1,2,3 so if u have an questions or i did it wrong i will fix it <3

   

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In a certain neighborhood, there's a sagging power line between two utility poles. The utility poles are 50 feet tall and 120 fe
e-lub [12.9K]
<h3>Answer:  33.75 feet</h3>

In fraction form, this value is equal to 135/4

33.75 ft is equivalent to 33 ft, 9 inches.

===============================================

Explanation:

Refer to the diagram below.

The key point to start with is point H, which is the vertex of the parabola.

Recall that vertex form is

y = a(x-h)^2 + k

What we'll do is plug in the vertex (h,k) = (60,30) which is the location of point H. We'll also plug in (0,45) which is the y intercept, aka the location of point C.

So,

y = a(x-h)^2 + k

y = a(x-60)^2 + 30 .... plug in vertex

45 = a(0-60)^2 + 30 .... plug in y intercept coordinates

45 = a(-60)^2 + 30

45 = a(3600) + 30

45 = 3600a + 30

45-30 = 3600a

3600a = 15

a = 15/3600

a = 1/240

This then means:

y = a(x-h)^2 + k

y = (1/240)(x-60)^2 + 30

This is the equation of our parabola. Plug in x = 30 to determine the height of point K

y = (1/240)(x-60)^2 + 30

y = (1/240)(30-60)^2 + 30

y = (1/240)(-30)^2 + 30

y = (1/240)(900) + 30

y = 15/4 + 30

y = 15/4 + 120/4

y = 135/4

y = 33.75

Therefore, the height of the power line, when it is 30 feet away from one of the poles, is 33.75 feet. This is the y coordinate of point K.

Side note: 33.75 ft = 33 ft + 0.75 ft = 33 ft + 12*0.75 in = 33 ft + 9 inches

8 0
2 years ago
If f(x) = 6 – 5x and g(x) = 4x – 1, evaluate f(x) – g(x) for x = –2.
pogonyaev
Hello :
<span>f(x) = 6 – 5x and g(x) = 4x – 1
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3 years ago
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