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galina1969 [7]
3 years ago
5

Tim records how fast he can run a mile over five consecutive weeks. He records his runs, in minutes, to be 6, 5.6, 5.4, 5.2, and

5. What is the range of Tim's times?
Mathematics
2 answers:
tekilochka [14]3 years ago
6 0

Answer:

1

Step-by-step explanation:

You are finding the range, which can be found by subtracting the smallest number from the greatest number.

Smallest number = 5, Greatest number = 6

6 - 5 = 1

1 is your range answer.

~

Shtirlitz [24]3 years ago
4 0

Answer:

The range is 1

Step-by-step explanation:

To calculate range, you subtract the lowest value from the highest value.

The lowest is 5 here and the highest is 6. The range is 6-5 which equals 1.

You might be interested in
Find sinϴ and cosϴ if tanϴ=1/4 and sinϴ>0
eduard
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2787701

_______________


\mathsf{tan\,\theta=\dfrac{1}{4}\qquad\qquad(sin\,\theta\ \textgreater \ 0)}\\\\\\
\mathsf{\dfrac{sin\,\theta}{cos\,\theta}=\dfrac{1}{4}}\\\\\\
\mathsf{4\,sin\,\theta=cos\,\theta\qquad\quad(i)}


Square both sides:

\mathsf{(4\,sin\,\theta)^2=(cos\,\theta)^2}\\\\
\mathsf{4^2\,sin^2\,\theta=cos^2\,\theta}\\\\
\mathsf{16\,sin^2\,\theta=cos^2\,\theta\qquad\qquad(but,~cos^2\,\theta=1-sin^2\,\theta)}\\\\
\mathsf{16\,sin^2\,\theta=1-sin^2\,\theta}

\mathsf{16\,sin^2\,\theta+sin^2\,\theta=1}\\\\
\mathsf{17\,sin^2\,\theta=1}\\\\
\mathsf{sin^2\,\theta=\dfrac{1}{17}}\\\\\\
\mathsf{sin\,\theta=\pm\,\sqrt{\dfrac{1}{17}}}\\\\\\
\mathsf{sin\,\theta=\pm\,\dfrac{1}{\sqrt{17}}}


Since \mathsf{sin\,\theta} is positive, you can discard the negative sign. So,

\mathsf{sin\,\theta=\dfrac{1}{\sqrt{17}}\qquad\quad\checkmark}


Substitute this value back into \mathsf{(i)} to find \mathsf{cos\,\theta:}

\mathsf{4\cdot \dfrac{1}{\sqrt{17}}=cos\,\theta}\\\\\\
\mathsf{cos\,\theta=\dfrac{4}{\sqrt{17}}\qquad\quad\checkmark}


I hope this helps. =)


Tags:   <em>trigonometric identity relation trig sine cosine tangent sin cos tan trigonometry precalculus</em>

7 0
3 years ago
list as many combinations of three dimensions you can come up with that would give you a volume if 1536 cubic feet.
Monica [59]

Answer:

1.) Length = 8ft, width = 8ft, height = 24ft

2.) Length = 8ft, width = 16ft, height = 12ft

3.) Length = 8ft, width = 24ft, height = 8ft

4.) Length = 8ft, width = 32ft, height = 6ft

5.) Length = 6ft, width = 8ft, height = 32ft

6.) Length = 16ft, width = 4ft, height = 24ft

7) Length = 12ft, width = 8ft, height = 16ft

8.) Length = 2ft, width = 64ft, height = 12ft

9.) Length = 48ft, width = 16ft, height = 2ft

Step-by-step explanation:

To obtain a volume of 1536 cubic feet:

This means Length × width × Height equals 1536ft^3

1.) Length = 8ft, width = 8ft, height = 24ft

2.) Length = 8ft, width = 16ft, height = 12ft

3.) Length = 8ft, width = 24ft, height = 8ft

6 0
3 years ago
Please help if your intelligent at 9th grade math
Law Incorporation [45]

Answer:

whats the question????

3 0
4 years ago
Read 2 more answers
Ayudaaaa por favor es urgente​
ss7ja [257]

Answer:

use trig

Step-by-step explanation:

sin(15) = 100/x

x = 100/sin(15)

use calculator

8 0
3 years ago
(-4)-(-2)-{(-5)-[(-7)+(-3)-(-8)]}
olasank [31]

Answer:

1

Explanation:

I used the calculator.

4 0
3 years ago
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