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Gwar [14]
3 years ago
10

PLEASE HELP!!!!!!!!!!!!1

Mathematics
1 answer:
skelet666 [1.2K]3 years ago
5 0
A. Let x = cheese and
y = chocolate
2x + y = 25
x + y = 20

B. Subtract the second equation from the first.
2x + y = 25
-(x + y = 20)
-—————
x = 5

Plug 5 back in to the second equation and solve for y.
x + y = 20
5 + y = 20
Subtract 5 from both sides.
y = 15
5 cheese and 15 chocolate

Used elimination method because coefficients on the y values were both 1 so it was easy to subtract the equations and eliminate the y variable.


You might be interested in
_____ have congruent corresponding parts.
aniked [119]

Answer:

Two congruent figures

Step-by-step explanation:

Here we have to use the definition of congruent.

Congruent means equal to each other.

Example.

If the two triangles said be congruent, their corresponding angles and corresponding sides are equal.

They will have to same size of the sides and same measure of angles.

Two equal polygons, that is two congruent figures.

Hope this will help you.

Thank you.

4 0
3 years ago
Tamara and Clyde got different answers when dividing 2x4 + 7x3 – 18x2 + 11x – 2 by 2x2 – 3x + 1. Analyze their individual work.
lys-0071 [83]

<em>Note: As you may have unintentionally missed to add the different answers, based on which we had to check who solved correctly between Tamara and Clyda's work. </em>

<em>But, I am actually solving the expression and you must note that whoever (between Tamara and Clyda's work) may have got the same answer or match the answer with mine, would be the one who solved correctly.</em>

Answer:

We conclude that whoever (between Tamara and Clyda's work) may have got the answer as x^2+5x-2 after dividing   2x^4\:+\:7x^3\:-\:18x^2\:+\:11x\:-\:2 by 2x^2\:-\:3x\:+\:1  , would be the one who solved it correctly.

Step-by-step explanation:

Considering the expression

                            2x^4\:+\:7x^3\:-\:18x^2\:+\:11x\:-\:2

Lets divide the expression by 2x^2\:-\:3x\:+\:1

Solution Steps:

\frac{2x^4+7x^3-18x^2+11x-2}{2x^2-3x+1}

Factorizing

2x^4+7x^3-18x^2+11x-2:\quad \left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)

\frac{\left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)}{2x^2-3x+1}

Factorizing

2x^2-3x+1:\quad \left(2x-1\right)\left(x-1\right)

\frac{\left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)}{\left(2x-1\right)\left(x-1\right)}

\mathrm{Cancel\:}\frac{\left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)}{\left(2x-1\right)\left(x-1\right)}:\quad x^2+5x-2

x^2+5x-2

Thus,

\frac{2x^4+7x^3-18x^2+11x-2}{2x^2-3x+1}=x^2+5x-2

Therefore, we conclude that whoever (between Tamara and Clyda's work) may have got the answer as x^2+5x-2 after dividing   2x^4\:+\:7x^3\:-\:18x^2\:+\:11x\:-\:2 by 2x^2\:-\:3x\:+\:1  , would be the one who solved it correctly.

Keywords: expression, division

Learn more about expression division from brainly.com/question/1575482

#learnwithBrainly

3 0
3 years ago
Read 2 more answers
A right circular cylinder has a diameter of 16 mm and a height of 12 mm. what is the volume of the cylinder in terms of π?
valina [46]
Volume of the cylinder = hr²π

diameter = 2 × radius
16 = 2 × r
r = 16/2
r = 8 mm

V = hr²π
V = 12 × 8² × π
V = 12 × 64 × π
V = 768π  mm³
8 0
3 years ago
Read 2 more answers
The GCF of 18 and 27 is _______.
Gnoma [55]

Answer:

9

Step-by-step explanation:

The factors of 18 are : 1, 2, 3, 6, 9, 18

The factors of 27 are : 1, 3, 9, 27

The common factors are : 1, 3, 9

The gcf is 9

3 0
3 years ago
Read 2 more answers
16. Jerome is a co-owner of a small company and received 1/3 of the company’s profits this year. What were the company’s overall
AlekseyPX
Remark
The trick to this question is realizing what you took 1/3 of. Did you take it of the 150000 or is it 1/3 of some total you have to find. I don't think you could come up with a third choice. 

It turns out that the answer is 1/3 of a number you don't know.

Equation
(1/3) x = 150000 Multiply both sides by 3
3*(1/3) x = 150000 * 3
x = 150000 * 3
x = 450000

Conclusion
The amount the company makes is 450000 dollars / year.
6 0
3 years ago
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