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____ [38]
2 years ago
10

Find the m, b, and write the equation for the following graph:

Mathematics
1 answer:
geniusboy [140]2 years ago
3 0

Answer:

y=3

Step-by-step explanation:

m=0

b=3

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-3x^2 plus 24x = 27 <br> complete the square
Rudik [331]

You can divide the whole expression by -3:

-3x^2+24x=27 \iff x^2-8x = -9

Recalling that

(x-a)^2=x^2-2ax+a^2

Let's compare the middle term:

-8x = -2ax \iff a=4

So, we want to complete

(x-4)^2 = x^2-8x+16

Which differs from x^2-8x by 16. So, if we add 16 to both sides, we have

x^2-8x=-9 \iff x^2-8x+16=7 \iff (x-4)^2=7

3 0
3 years ago
Read 2 more answers
A study of five hundred adults found that the number of hours they spend on social networking sites each week is normally distri
Nata [24]
Margin of error formula:
ME = z * (Sigma) / √ n
z = 1.96 for a 95 % confidence interval;
Sigma = 3 ( the population standard deviation )
n = 500
ME = 1.96 * 3 / √500 =
= 1.96 * 3 / 22.36 =
= 5.88 / 22.36 = 0.263
Answer:
The margin error for a 95% confidence interval is 0.263.
6 0
3 years ago
Evaluate this expression for the given value of the variable 4 (d+7);d=-2
Paha777 [63]

Exact Form:

d

=

−

7

−

√

47

2

,

−

7

+

√

47

2

d

=

-

7

-

47

2

,

-

7

+

47

2

Decimal Form:

d

=

−

0.07217269

…

,

−

6.92782730

…

6 0
2 years ago
Read 2 more answers
Find the equation in standard form of the line passing through the points 3,-4 and 5,1
aliina [53]

Answer:

5x - 2y - 23 = 0

Step-by-step explanation:

Line is passing through the points (3,\:-4)= (x_1, \:y_1) \: \&\: (5,\: 1)= (x_2,\:y_2)

Equation of line in two point form is given as:

\frac{y -y_1 }{y_1 -y_2 }  =  \frac{x -x_1 }{x_1 -x_2 } \\  \\  \therefore \:  \frac{y -( - 4) }{ - 4 -1}  =  \frac{x -3 }{3 -5 } \\  \\  \therefore \:\frac{y  +  4 }{ - 5}  =  \frac{x -3 }{ - 2 } \\  \\  \therefore \: \frac{y  +  4 }{  5}  =  \frac{x -3 }{  2 } \\  \\  \therefore \:  2(y + 4) = 5(x - 3) \\ \therefore \:  2y + 8 = 5x - 15 \\ \therefore \: 5x - 15 - 2y - 8 = 0 \\  \red{ \boxed{ \bold{\therefore \: 5x - 2y - 23 = 0}}} \\ is \: the \: required \: equation \: of \: line \: in \:  \\ standard \: form.

7 0
3 years ago
What have I done wrong and where please help me
lys-0071 [83]
12x - 18 - 4x -2
12x - 4x = 8x (yours 12x - 4x = 8)
-18 - 2 = -20 (yours -18 -1 = 17)

answer:

8x - 20
6 0
3 years ago
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