Let's represent the two numbers by x and y. Then xy=60. The smaller number here is x=y-7.
Then (y-7)y=60, or y^2 - 7y - 60 = 0. Use the quadratic formula to (1) determine whether y has real values and (2) to determine those values if they are real:
discriminant = b^2 - 4ac; here the discriminant is (-7)^2 - 4(1)(-60) = 191. Because the discriminant is positive, this equation has two real, unequal roots, which are
-(-7) + sqrt(191)
y = -------------------------
-2(1)
and
-(-7) - sqrt(191)
y = ------------------------- = 3.41 (approximately)
-2(1)
Unfortunately, this doesn't make sense, since the LCM of two numbers is generally an integer.
Try thinking this way: If the LCM is 60, then xy = 60. What would happen if x=5 and y=12? Is xy = 60? Yes. Is 5 seven less than 12? Yes.
The price is 36 because 40% of 65 is 29 and 65-29 equals 36.
Answer:
D
Step-by-step explanation:
It is because you can see the line pass through the value 0 in x-axis while 6 in y-axis which gives the first coordinate (x,y) = (0,6) and the line also past through the value of 5 in x-axis and 1 in y-axis which gives the second coordinate is (1,5).
So it is true that the line did go through at points (0,6) and (1,5).
Step-by-step explanation:
x2 + 10x + 24
x2 + 6x + 4x + 24
x(x + 6) + 4(x + 6)
(x + 6) (x + 4)
