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siniylev [52]
3 years ago
6

I need help urgently please!!!!! Will absolutely mark the brainiest whoever answers this correctly!

Mathematics
1 answer:
yulyashka [42]3 years ago
5 0
If i plug it into my calculator i get 9914 as my answer,

Explanation:
but if that’s not the right answer lmk and i can solve it a different way!
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A number is chosen at random from 1 to 25. Find the probability of selecting
pogonyaev

Answer:

28

Step-by-step explanation:

8 0
3 years ago
5 – 6x = 8x + 17 and simplify <img src="https://tex.z-dn.net/?f=%5Cfrac%7B-6%7D%7B7%7D" id="TexFormula1" title="\frac{-6}{7}" al
NikAS [45]

Answer:

x = -6/7

Step-by-step explanation:

5 – 6x = 8x + 17

-5                 - 5           Subtract 5 from both sides

-6x = 8x + 12

-8x   - 8x                     Subtract 8x from both sides

-14x = 12                      Divide both sides by -14

x = -12/14                     Simplify

x = -6/7

7 0
3 years ago
Ian invested $90,000 in an account paying an interest rate of 2.6% compounded quarterly. Assuming no deposits or withdrawals are
barxatty [35]

Answer:

A≈<u>107902</u>

Step-by-step explanation:

8 0
2 years ago
Solve: 6x + 10 = 4x -8. Determine how many solutions? (exactly one, infinitely many, no solution)
Vesnalui [34]
  • Answer:

<em>x = - 9</em>

  • Step-by-step explanation:

<em>6x + 10 = 4x - 8</em>

<em>6x - 4x = - 10 - 8</em>

<em>2x = - 18</em>

<em>x = - 18 : 2</em>

<em>x = - 9</em>

7 0
3 years ago
In abc above,what is the length of ad​
Nezavi [6.7K]

Answer:

B

Step-by-step explanation:

First calculate BD using sine ratio in Δ BCD and the exact value

sin60° = \frac{\sqrt{3} }{2}, thus

sin60° = \frac{opposite}{hypotenuse} = \frac{BD}{BC} = \frac{BD}{12} = \frac{\sqrt{3} }{2} ( cross- multiply )

2BD = 12\sqrt{3} ( divide both sides by 2 )

BD = 6\sqrt{3}

-----------------------------------------------------------

Calculate AD using the tangent ratio in Δ ABD and the exact value

tan30° = \frac{1}{\sqrt{3} } , thus

tan30° = \frac{opposite}{adjacent} = \frac{AD}{BD} = \frac{AD}{6\sqrt{3} } = \frac{1}{\sqrt{3} } ( cross- multiply )

\sqrt{3} AD = 6\sqrt{3} ( divide both sides by \sqrt{3} )

AD = 6 → B

4 0
3 years ago
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