Answer:
Each teacher will have 21 students
Step-by-step explanation:
273 divded by 21 = 21
Answer: OPTION B.
Step-by-step explanation:
Given the following System of equations:
You can use the Elimination Method to solve it. The steps are:
1. You can mutliply the second equation by -3.
2. Then you must add the equations.
3. Solve for the variable "y".
Then:
4. Now that you know the value of the variable "y", you must substitute it into any original equation.
5. The final step is to solve for "x" in order to find its value.
Then:
Therefore, the solution is:
If b is in the first position then c can be in any 1 of the remaining 6 positions.
If we start with ab then the letter c can be in any one of 5 positions and if we have aab there are 4 possible positions for c and so on.
So the total number of possible sequences where b comes first = 6+5+4+3+2+1 = 21.
The same argument applies when c comes before b so that gives us 21 ways also.
So the answer is 2 *21 = 42 different sequences.
A more direct way of doing this is to use factorials:-
answer = 7! / 5! = 7 * 6 = 42.
( We divide by 5! because of the 5 a's.)
Pick an x-value between the interval givens. I’ll choose “1”. If you sub in one for both f(x) and g(x) you get that f(1) = -1.5 and g(1) = -0.5. Now you can divide f(1) by g(1) to get average rate of change. -1.5/-0.5 = 3.
