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soldi70 [24.7K]
4 years ago
13

Mel is skilled in identifying the technical, economic, and organizational feasibility of software. In which phase of SDLC should

Mel work?
A.
analysis
B.
design
C.
development
D.
implementation
Computers and Technology
1 answer:
kirill115 [55]4 years ago
5 0

SDLC refers to Software/System Development Life Cycle, which is defined as <em>a process involving various stages to ensure high-quality end product.</em>

It generally contains six phases: planning, analysis, design, implementation, testing, deployment, and maintenance.

A person with Mel’s level of capability should be dealing with the (A) analysis level of SDLC.

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The feedforward part of the conversation should do all of the following except __________.a.identify the toneb.introduce the pur
polet [3.4K]

Answer:

give leave taking clues

Explanation:

The feed forward part of the conversation should do all of the following except <u>give leave taking clues</u> a identify the tone introduce the purpose give leave-taking clues establish a time-frame

3 0
4 years ago
The size of the board is one of the differences between Elevens and Thirteens. Why is size not an abstract method?
Levart [38]

Answer:

The program keeps track of the size of the board in cards.size(). The sub class sets this by passing it into the constructor. After that, the subclass never cares about the size of the board, so it's not necessary to make it accessible with an abstract method. Any need for it is covered by cardIndexes method.

Explanation:

The differences between Elevens and Thirteens

The program keeps track of the size of the board in cards.size(). The sub class sets this by passing it into the constructor. After that, the subclass never cares about the size of the board, so it's not necessary to make it accessible with an abstract method. Any need for it is covered by cardIndexes method.

5 0
4 years ago
On early computers, every byte of data read or written was handled by the CPU (i.e., there was no DMA). What implications does t
grandymaker [24]

Answer:

Multiprogramming will be extremely difficult to be achieved.

Explanation:

If every byte of data read or written is handled by the CPU the implications this will have for multiprogramming are not going to be satisfactory.

This is because, unlike before, after the successful completion of the input and output process, the CPU of a computer is not entirely free to work on other instructions or processes.

5 0
3 years ago
Determine and prove whether an argument in English is valid or invalid. About Prove whether each argument is valid or invalid. F
yawa3891 [41]

Answer:

Each understudy on the respect roll got an A.  

No understudy who got a confinement got an A.  

No understudy who got a confinement is on the respect roll.  

No understudy who got an A missed class.  

No understudy who got a confinement got an A.  

No understudy who got a confinement missed class  

Explanation:

M(x): x missed class  

An (x): x got an A.  

D(x): x got a confinement.  

¬∃x (A(x) ∧ M(x))  

¬∃x (D(x) ∧ A(x))  

∴ ¬∃x (D(x) ∧ M(x))  

The conflict isn't considerable. Consider a class that includes a lone understudy named Frank. If M(Frank) = D(Frank) = T and A(Frank) = F, by then the hypotheses are overall evident and the end is counterfeit. Toward the day's end, Frank got a control, missed class, and didn't get an A.  

Each understudy who missed class got a confinement.  

Penelope is an understudy in the class.  

Penelope got a confinement.  

Penelope missed class.  

M(x): x missed class  

S(x): x is an understudy in the class.  

D(x): x got a confinement.  

Each understudy who missed class got a confinement.  

Penelope is an understudy in the class.  

Penelope didn't miss class.  

Penelope didn't get imprisonment.  

M(x): x missed class  

S(x): x is an understudy in the class.  

D(x): x got imprisonment.  

Each understudy who missed class or got imprisonment didn't get an A.  

Penelope is an understudy in the class.  

Penelope got an A.  

Penelope didn't get repression.  

M(x): x missed class  

S(x): x is an understudy in the class.  

D(x): x got a repression.  

An (ax): x got an A.  

H(x): x is on the regard roll  

An (x): x got an A.  

D(x): x got a repression.  

∀x (H(x) → A(x)) a  

¬∃x (D(x) ∧ A(x))  

∴ ¬∃x (D(x) ∧ H(x))  

Real.  

1. ∀x (H(x) → A(x)) Hypothesis  

2. c is a self-self-assured element Element definition  

3. H(c) → A(c) Universal dispatch, 1, 2  

4. ¬∃x (D(x) ∧ A(x)) Hypothesis  

5. ∀x ¬(D(x) ∧ A(x)) De Morgan's law, 4  

6. ¬(D(c) ∧ A(c)) Universal dispatch, 2, 5  

7. ¬D(c) ∨ ¬A(c) De Morgan's law, 6  

8. ¬A(c) ∨ ¬D(c) Commutative law, 7  

9. ¬H(c) ∨ A(c) Conditional character, 3  

10. A(c) ∨ ¬H(c) Commutative law, 9  

11. ¬D(c) ∨ ¬H(c) Resolution, 8, 10  

12. ¬(D(c) ∧ H(c)) De Morgan's law, 11  

13. ∀x ¬(D(x) ∧ H(x)) Universal hypothesis, 2, 12  

14. ¬∃x (D(x) ∧ H(x)) De Morgan's law, 13  

4 0
3 years ago
Assume that ip , jp , and tp have all been declared to be pointers to int and that result has been declared to be an array of 10
natita [175]

Answer:

The code to this question can be given as:

code:

tp = ip;

ip = jp;

jp = tp;

Explanation:

In this question, it is defined that write code for swapping values that swap the pointers, not the values they point to. So in this code, we assume that all the variable and its value is defined. we simply use the swapping rule that is the first value holds in the new variable and second value hold on the first variable and in the last second variable holds the value of the new variable. In this code, the value will be interchanged or swapped.

3 0
4 years ago
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