Given that the diameter: d= 0.0625 inch.
So, radius of the wire : r = = 0.03125 inch
Now the formula to find the cross-sectional area of wire ( circle) is:
A = πr²
= 3.14 * (0.03125)² Since, π = 3.14 and r = 0.03125
=3.14 * 0.000976563
= 0.003066406
= 0.00307 (Rounded to 5 decimal places).
Hence, cross-sectional area of a wire is 0.00307 square inches.
Hope this helps you!
Hie!! I will be solving the questions in the sequence of the attachments.
_______________________________________
4. As line SU and TV are intersecting each other at O.
A.T.Q, ∠UOV = (7x - 4)°
∠SOT = 87°
Then, ∠UOV = ∠SOT {Vertically Opposite Angles}
_______________________________________
5. radius = 17ft
circumference of circle = 2πr
_______________________________________
3. ∠1 and ∠2 - add to 180 (linear pair)
∠1 and ∠3 - equal (Vertically Opposite Angles)
∠3 and ∠4 - add to 180 (linear pair)
∠2 and ∠4 - equal (Vertically Opposite Angles)
_______________________________________
2. 160° + (6x - 16)° = 180° (linear pair)
