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3 years ago

15

Is a rectangular prism has a length width and height of 3/8cm, 5/8cm and 7/8 in a meter respectively then the volume of the pris

m is

1 answer:

myrzilka [38]3 years ago

4 0

The volume of a rectangular prism is given by the multiplication of its three dimensions: if $w, h, l$ are the width, height and length of the prism, the volume is

$V = w\cdot h\cdot l$

So, in your case, you have

$V = \dfrac{3}{8} \cdot \dfrac{5}{8} \cdot \dfrac{7}{8} = \dfrac{3\cdot 5 \cdot 7}{8\cdot 8 \cdot 8} = \dfrac{105}{512}$

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Fill in the table using this function rule y=27-4x

Elis [28]

Step 1: Y= 27 - 4x

To find X - intercept / zero, substitute Y = 0

0 = 27 - 4x

Step 2: 0 = 27 - 4x

Move variable to the left-hand side and change it's sign.

4x = 27

Step 3: 4x = 27

divide both sides of the equation by 4

X = 27/4

solution: X = 27/4

Alternate form: X = 6 3/4, X = 6.75

3 0

3 years ago

I really need help!! <br> what number is equivalent to the fraction?<br> 5<br> 9

dangina [55]

Answer:

0.55555555555555555555555555556

<em>(The 5 is repeating, so I rounded the last digit to 6.)</em>

Step-by-step explanation:

Divide 5/9. You get 0.5555... and the 5 is repeating.

5 0

3 years ago

PLZZZZZZ HEEEEEEEEELLLLLPPPPP<br> (will mark brainliest for correct answers)

alexdok [17]

Answer:

y=4

Step-by-step explanation:

3(9) +4y= 43

27+4y=43

4y=16

y=4

6 0

3 years ago

Find the Fourier series of f on the given interval. f(x) = 1, ?7 < x < 0 1 + x, 0 ? x < 7

Zolol [24]

$f(x)=\begin{cases}1&\text{for }-7$

The Fourier series expansion of $f(x)$ is given by

$\dfrac{a_0}2+\displaystyle\sum_{n\ge1}a_n\cos\frac{n\pi x}7+\sum_{n\ge1}b_n\sin\frac{n\pi x}7$

where we have

$a_0=\displaystyle\frac17\int_{-7}^7f(x)\,\mathrm dx$
$a_0=\displaystyle\frac17\left(\int_{-7}^0\mathrm dx+\int_0^7(1+x)\,\mathrm dx\right)$
$a_0=\dfrac{7+\frac{63}2}7=\dfrac{11}2$

The coefficients of the cosine series are

$a_n=\displaystyle\frac17\int_{-7}^7f(x)\cos\dfrac{n\pi x}7\,\mathrm dx$
$a_n=\displaystyle\frac17\left(\int_{-7}^0\cos\frac{n\pi x}7\,\mathrm dx+\int_0^7(1+x)\cos\frac{n\pi x}7\,\mathrm dx\right)$
$a_n=\dfrac{9\sin n\pi}{n\pi}+\dfrac{7\cos n\pi-7}{n^2\pi^2}$
$a_n=\dfrac{7(-1)^n-7}{n^2\pi^2}$

When $n$ is even, the numerator vanishes, so we consider odd $n$ , i.e. $n=2k-1$ for $k\in\mathbb N$ , leaving us with

$a_n=a_{2k-1}=\dfrac{7(-1)-7}{(2k-1)^2\pi^2}=-\dfrac{14}{(2k-1)^2\pi^2}$

Meanwhile, the coefficients of the sine series are given by

$b_n=\displaystyle\frac17\int_{-7}^7f(x)\sin\dfrac{n\pi x}7\,\mathrm dx$
$b_n=\displaystyle\frac17\left(\int_{-7}^0\sin\dfrac{n\pi x}7\,\mathrm dx+\int_0^7(1+x)\sin\dfrac{n\pi x}7\,\mathrm dx\right)$
$b_n=-\dfrac{7\cos n\pi}{n\pi}+\dfrac{7\sin n\pi}{n^2\pi^2}$
$b_n=\dfrac{7(-1)^{n+1}}{n\pi}$

So the Fourier series expansion for $f(x)$ is

$f(x)\sim\dfrac{11}4-\dfrac{14}{\pi^2}\displaystyle\sum_{n\ge1}\frac1{(2n-1)^2}\cos\frac{(2n-1)\pi x}7+\frac7\pi\sum_{n\ge1}\frac{(-1)^{n+1}}n\sin\frac{n\pi x}7$

3 0

3 years ago

Select the correct answer.

sergejj [24]

G(x)/f(x) will be simplified to (x+3)(x-3)/2-x^1/2,
which will give you [0,4) ∪(4, ∞).
Choice B

5 0

3 years ago