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Katen [24]
3 years ago
10

Select from the drop-down menus to correctly complete each statement. Quadrilateral ABCD can be mapped onto quadrilateral EFGH w

ith a followed by a . The figures are . Coordinate plane with x axis from negative -10 to 2 and y axis from negative 2 to 10. Quadrilateral A B C D has vertices A begin ordered pair negative 9 comma 5 end ordered pair, B begin ordered pair negative 7 comma 3 end ordered pair, C begin ordered pair negative 5 comma 4 end ordered pair, and D begin ordered pair negative 6 comma 8 end ordered pair. Quadrilateral E F G H has vertices E begin ordered pair negative 2.5 comma negative 4.5 end ordered pair, F begin ordered pair negative 1.5 comma negative 3.5 end ordered pair, G begin ordered pair negative 2 comma negative 2.5 end ordered pair, and H begin ordered pair negative 4 comma negative 3 end ordered pair.
Mathematics
1 answer:
ICE Princess25 [194]3 years ago
8 0
This can be done with a dilation followed by a rotation.

When you plot the points and compare the coordinates, you can see that the coordinates of E, the image of A, are cut in half, the x- and y-values are swapped, and the y-value is negated.  A dilation will cut it in half, and a rotation will swap the coordinates and negate them.
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A city grid of Anytown, USA is shown on the grid below. The fire department is represented by quadrilateral RSTU. Another fire d
Alekssandra [29.7K]
Answer: option d. C (0,3), D (0,5).

Justification:

1) The x - coordinates of the vertices A and B are shown in the diagrama, They are both - 4, so the new vertices C and D must be in a line parallel to y = - 4.

2) The y-coordinates of the  vertices A and B are also shown in the diagrama. They  are equal to 3 and 5 respectively.

3) We can see that the new points C and D must be over a parallel line to y = - 4 and that their distance to the points A and B has to be the same distance of the point R and S to U and T.

That distance is 4, so the line may be y = - 7 or y = 0.

4) If the line is y = 7 the points C and D would have coordinates (-7,3) and (-7,5), but this points are not among the options.

5) If the line is y = 0 the points C and D would have coordinates (0, 3) and (0,5), which is precisely the points of the option d. That is the answer.



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3 years ago
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krek1111 [17]
Answer is B standard
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3 years ago
In triangle PQR, PR = 23mm, QR = 39mm, and m<R = 163 degrees. Find the area of the triangle to the nearest tenth.
Schach [20]

Answer: 131.1287 square mm (approx)

Step-by-step explanation:

The area of a triangle,

A=\frac{1}{2} \times s_1\times s_2\times sin \theta

Where s_1 and s_2 are adjacent sides and \theta is the include angle of these sides,

Here PR and QR are adjacent sides and ∠R is the included angle of these sides,

Thus, we can write,

s_1 = PR= 23\text{ mm}, s_2=QR=39\text{ mm} and \theta = 163^{\circ},

Thus, the area of the triangle PQR,

A=\frac{1}{2} \times 23\times 39\times sin163^{\circ}

A=\frac{262.257419136}{2} = 131.128709568\approx 131.1287\text{ square mm}

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I think the answer is shelter B
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