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musickatia [10]
3 years ago
12

4. Does the scatterplot have positive correlation, negative correlation, or no correlation?

Mathematics
1 answer:
bija089 [108]3 years ago
5 0

Answer:

Negative Correlation

Step-by-step explanation:

Since the points are approximately lined up in a linear line pointing toward the bottom right, the slope of the best fit line would be a negative value. So the scatter plot shows a negative correlation.

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Amplitude is correct
The vertical shift is correct
and the horizontal shift is correct
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A triangle has a height of 8 feet and an area of 48 square feet. Find the base.
weqwewe [10]
The base of the triangle is 12 because area of a triangle is 1/2 base times height
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3 years ago
If Julie invests $9,250 at a rate of 7%, compounded weekly, find the value of the investment after 5 years. $13,455.78
STatiana [176]
What is that $13,455.78? Something? I did this and got $13,122.76.  Here's how I did it:
Use this formula
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raise the value inside the parenthesis to the power of 260:
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6 0
3 years ago
Aaron is staying at a hotel that charges $99.95 per night plus tax for a room. A tax of 7% is applied to the room rate, and an a
Serjik [45]

Answer: $543.7325

Step-by-step explanation:

room rate = $99.95 / night

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Therefore, tax fee = 7% of $99.95

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7 0
3 years ago
Why is it necessary to use the absolute value of the difference when finding the distance on a number line, but not necessary wh
padilas [110]
Remember that the distance on a number line is given by the formula: d=|x_{2}-x_{1}|
where 
d is the distance between the points. 
x_{2} is the second point in the number line.  
x_{1} is the first point in the number line.
Now, suppose we are trying to find the distance between the points -1 and -5; our first point is -1, so x_{1}=-1, and our second point is -5, so x_{2}=-5. Suppose we are going to find the distance between the two point without using absolute value:
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Now, the distance between two coordinates on a plane is given by the formula: d= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}
where
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(x_{1},y_{2}) are the coordinates of the first point
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Notice that (x_{2}-x_{1})^2 and (y_{2}-y_{1})^2 are squared, so it doesn't matter if we get a negative distance because a negative number raised to an even power (like 2) is always positive; therefore we don't need absolute value in this case because we won't ever get a negative distance. 


7 0
3 years ago
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