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3 years ago

Distribute and combine like terms. 3(5a-4b-6)-2(2a+2b+4) I need help

Mathematics

1 answer:

jek_recluse [69]3 years ago

4 0

Answer:

11a-16b-26

Step-by-step explanation:

Distribute 3 into first equation.

15a-12b-18.

Distribute -2 into second equation.

-4a-4b-8.

Rewrite as one equation 15a-12b-18-4a-4b-8.

Combine like terms 11a-16b-26

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A scientist discovers a new way to produce vitamin C. In 15 hours, 678 kilograms are produced. In 25 hours, 1018 kilograms are p

satela [25.4K]

Answer:

The equation of the line is $y = 34\cdot x + 168$ .

Step-by-step explanation:

According to Analytical Geometry, we know that any equation of the line can be determined by knowing two distinct points on Cartesian plane. From statement we get that:

$y(15\,h) = 678\,kg$ (1)

$y (25\,h) = 1018\,kg$ (2)

By applying the definition of the equation of the line, we form this system of two linear equations with two variables:

$15\cdot m + b = 678$ (3)

$25\cdot m + b = 1018$ (4)

By algebraic mean we get the following solution:

$m = 34\,\frac{kg}{h}$ and $b = 168\,kg$

And the equation of the line is $y = 34\cdot x + 168$ .

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3 years ago

Describe how to find the number of weeks equal to 56 days

shutvik [7]

Umm im not sure maby do 7x diffrent numbers to find out idk sorry

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4 years ago

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350 is what percentage of 50?

denpristay [2]

Answer:

175

Step-by-step explanation:

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3 years ago

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What polynomial should be added to 4x²+5x-8 in order to equal 0?

Klio2033 [76]

4x^2 + 5x - 8 + (- 4x^2 - 5x + 8) = 0

all ur doing is changing the signs so they will cancel each other out.

so ur adding : -4x^2 - 5x + 8

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4 years ago

Sin(-180° + θ) = ________

Svet_ta [14]

Answer:

$\sin\left(-180^o+\theta\right)=-\sin\left(\theta\right)$

Step-by-step explanation:

We need to find the value of $\sin(-180^o+ \theta)$

So let's apply formula

$\sin\left(A+B\right)=\sin\left(A\right)\cos\left(B\right)+\sin\left(B\right)\cos\left(A\right)$

$\sin\left(-180^o+\theta\right)=\sin\left(-180^o\right)\cos\left(\theta\right)+\sin\left(\theta\right)\cos\left(-180^o\right)$

$\sin\left(-180^o+\theta\right)=0\cdot\cos\left(\theta\right)+\sin\left(\theta\right)\cdot\left(-1\right)$

$\sin\left(-180^o+\theta\right)=0-\sin\left(\theta\right)$

$\sin\left(-180^o+\theta\right)=-\sin\left(\theta\right)$

8 0

3 years ago