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pochemuha
3 years ago
8

A ^-4 / a ^-6 please simplify and show your work if possible <:D

Mathematics
1 answer:
kipiarov [429]3 years ago
7 0

\bf ~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \cfrac{a^{-4}}{a^{-6}}\implies a^{-4}\cdot a^6\implies a^{-4+6}\implies a^2

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If DEF and MNO are two triangles such that DE=MN and EF=NO, which of the following would be sufficient to prove that triangles a
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Answer:

  D.  ∠E ≅ ∠N

Step-by-step explanation:

The pair of sides meet at vertex E in ∆DEF and at vertex N in ∆MNO. Since the sides that make up angles E and N are shown congruent, it is sufficient to show ...

  ∠E ≅ ∠N

Then the SAS congruence postulate can be claimed.

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<em>Additional comment</em>

The alternative is to show DF ≅ MO. That would allow you to claim SSS congruence. That is not an answer choice.

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Step-by-step explanation:

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Read 2 more answers
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Answer:

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Step-by-step explanation:

Please find the attached file for a clearer understanding.

SOHCAHTOA

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