Question

An isosceles trapezoid has base angles of 45° and bases of lengths 8 and 14. The area of the trapezoid is

Answer 1

Area = 0.5 ( sum of two bases ) * height


height = (14- 8)/2 = 3


Area = 0.5 x 3 x (14 + 8 ) = 33 sq units

Answer 2

Answer:

Option A is correct.      

Step-by-step explanation:

Given an isosceles trapezoid has base angles of 45° and bases of lengths 8 and 14. we have to find the area of isosceles trapezoid.

An isosceles trapezoid has base angles of 45° and bases of lengths 8 and 14.

From the figure attached , we can see an isosceles trapezoid ABCD,

AB = 8cm and CD=14cm

So we have to find the value of AE which is the height of Trapezoid in order to find area.

In ΔAED

$tan\angle 45 =\frac{AE}{ED}$

⇒ $AE=1\times 3$

∴ AE = DE =3cm

$\text{The area of the trapezoid=}\frac{h}{2}\times (a+b)$

h=3cm, a=14cm, b=8cm

$Area=\frac{3}{2}\times(14+8)=\frac{3}{2}\times 22=33 units^2$

hence, $\text{The area of the trapezoid is }33 units^2$

Option A is correct.