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2 years ago

A plane can be described by any two non-collinear points True or False

Mathematics

2 answers:

VashaNatasha [74]2 years ago

7 0

Its 3 not 2. Im pretty sure

Karolina [17]2 years ago

4 0

Answer:

False

Step-by-step explanation:

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Solve (x +9)2 = 25.

alexandr1967 [171]

Answer:

$x = - 4 \: or \: x = - 14$

Step-by-step explanation:

We have been given the equation

$(x + 9) {}^{2} = 25$

and we are asked to apply the square root property of equality to our given a equation and isolate the variable

First, take the square root of both sides of our equation

$\sqrt{(x + 9) {}^{2} } = \sqrt{25}$

$x + 9 = \: 15$

$x + 9 = 5 \: or \: x + 9 = - 5$

$x + 9 - 9 = 5 - 9 \: or \: x + 9 - 9 = - 5 - 9$

$x = - 4 \: or \: x = - 14$

THEREFORE, THERE ARE TWO SOLUTIONS FOR OUR GIVEN EQUATION

$x + 9 = 5 \: then \: x = - 4. \\ x + 9 = - 5 \: then \: x = - 14$

PLEASE MAKR ME BRAINLIEST IF YOU ARE HAPPY WITH THE ANSWER

8 0

3 years ago

X + (-9) + 9 = 8 solve the equation using mental math

Studentka2010 [4]

Answer:

X=8 simplify equation

Step-by-step explanation:

-9+9=0

8 0

3 years ago

Makayla is teaching Rodney how to construct a square inscribed in a circle.

Yuliya22 [10]

Answer:

Step-by-step explanation:

6 0

3 years ago

Determine whether the equation x^3 - 3x + 8 = 0 has any real root in the interval [0, 1]. Justify your answer.

nikdorinn [45]

Answer:

The equation does not have a real root in the interval $\rm [0,1]$

Step-by-step explanation:

We can make use of the intermediate value theorem.

The theorem states that if $f$ is a continuous function whose domain is the interval [a, b], then it takes on any value between f(a) and f(b) at some point within the interval. There are two corollaries:

If a continuous function has values of opposite sign inside an interval, then it has a root in that interval. This is also known as Bolzano's theorem.
The image of a continuous function over an interval is itself an interval.

Of course, in our case, we will make use of the first one.

First, we need to proof that our function is continues in $\rm [0,1]$ , which it is since every polynomial is a continuous function on the entire line of real numbers. Then, we can apply the first corollary to the interval $\rm [0,1]$ , which means to evaluate the equation in 0 and 1:

$f(x)=x^3-3x+8\\f(0)=8\\f(1)=6$

Since both values have the same sign, positive in this case, we can say that by virtue of the first corollary of the intermediate value theorem the equation does not have a real root in the interval $\rm [0,1]$ . I attached a plot of the equation in the interval $\rm [-2,2]$ where you can clearly observe how the graph does not cross the x-axis in the interval.

6 0

3 years ago

Which of the capital letters G, I, J, L, or Q has at least one line of symmetry?

gladu [14]

I is the right one because it is a half and they both look the same

3 0

3 years ago