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4 years ago

10

A person's emotional quotient (EQ) is found by multiplying emotional age by 100 and dividing by chronological age. Using this in

formation, if a 21 yr old person has an EQ of 97 what is that person's emotional age?

1 answer:

pychu [463]4 years ago

6 0

Setup an equation...
97=100x/21
Cross multiply to solve.
100x=97(21)
100x=2037
X=20.37 years or to round 20 years

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Your sports drink bottle is 5/6 full. After practice, the bottle is 3/8 full. Write the difference of the amounts after practice

Rasek [7]

5/6-3/8=11/24
hope this helps

4 0

3 years ago

Solve using addition method<br><br> 3x-3y+2z=7<br> 3x+y-3z=-5<br> 7x-y-2z=0

frozen [14]

3x - 3y + 2z = 7
3x + 1y - 3z = -5 ⇒ 6x - 2y - 1z = 2 ⇒ 42x - 14y -   7z = 14
7x - 1y - 2z = 0   ⇒ 7x - 1y - 2z = 0 ⇒ <u>42x -   6y - 12z = 0 </u>
      -20y - 19z = 14
          -20y + 20y - 19z = 14 + 20y
      <u />    <u>-19z</u> = <u>14 + 20y</u>
          -19    -19
      z = -14/19 - 1 1/19y
       3x - 3y + 2(-14/19 - 1 1/19y) = 7
   3x - 3y - 1 9/19 - 2 2/19y = 7
           3x - 5 2/19y - 1 9/19 = 7
       <u> +1 9/19 +1 9/19 </u>
       3x - 5 2/19y = 8 9/19
        3x - 3x - 5 2/19y = 8 9/19 - 3x
      <u />    <u>-5 2/19y</u> = <u>8 9/19 - 3x</u>
       -5 2/19 -5 2/19
       y = -1 64/97 + 57/97x
       3x - 3(-1 64/97 + 57/97x) + 2(-14/19 - 1 1/19y) = 7
      3x + 4 95/97 + 1 74/97x - 1 9/19 - 2 2/19y = 7
   4 74/97x - 2 2/19y + 3.5056972328 = 7
   <u> -3.5056972328   -3.5056972328</u>
      4 74/97x - 2 2/19y = 3.494302767
      4 74/97x + 2 2/19y - 2 2/19y = 3.494302767 + 22/19y
      <u>4 74/97x</u> = <u>3.494302767 + 2 2/19</u>
       4 74/97    4 74/97
       x = 0.7336523126 + 0.4420141262y
3(0.733652316 + 0.4420141262y) - 3(-1 64/97 + 57/97x) + 2(-14/19 - 1 1/19y)=7
    2.200956948 + 1.326042379y + 4 95/97 - 1 74/97x - 1 9/19 - 2 2/19y = 7    -1 74/97x - 0.7792207789y + 5.706654181 = 7
   <u>    -5.706654181    -5.70665418</u>
   -1 74/97x - 0.7792207789y = 1.293345820
(x, y, z) = (0.733652316 + 0.4420141262, -1 64/97 + 57/97x, -14/19 - 1 1/19y)

6 0

3 years ago

How do I turn 35 into a fraction?

timofeeve [1]

Every number is already a fraction, it just may not be written in the fraction form. 35 in the fraction written form is 35/1

8 0

3 years ago

Can someone please help and explain its due in a littleee

jek_recluse [69]

$f(x) = {x}^{2} - 3x + 2$

<h2>••••••••••••••••••••••••••••••••••••••••</h2>

put x = (-1)

$f( - 1) = {( - 1)}^{2} - 3 \times ( - 1) + 2 \\ \\ 1 + 3 + 2 \\ \\ 6.$

<h2>••••••••••••••••••••••••••••••••••••••••</h2>

put x = (z)

$f(z) = {z}^{2} - 3 \times z + 2 \\ \\ {z}^{2} - 3z + 2 \\ \\ {z}^{2} - 2z - z + 2 \\ \\ z(z - 2) - 1(z - 2) \\ \\ (z - 1)( z -2 ) \\ \\ (z - 1) = 0 \: \: , \: \: (z - 2) = 0\\ \\ z = 1 \:, \: 2$

<h2>••••••••••••••••••••••••••••••••••••••••</h2>

put x = (x+1)

$f(x + 1) = {x}^{2} - 3x + 2 \\ \\ {(x + 1)}^{2} - 3 (x + 1) + 2 \\ \\ {x}^{2} + 1 + 2x - 3x - 3 + 2 \\ \\ {x}^{2} - x \\ \\ x(x - 1) \\ \\ x(x - 1) = 0 \\ \\ x - 1 = \frac{0}{x} \\ \\ x - 1 = 0 \\ \\ x = 1.$

<h2>•••••••••••••••••••••••••••••••••</h2>

put x = (√2 + 1 )

$f( \sqrt{2} + 1) = {x}^{2} - 3x + 2 \\ \\ {( \sqrt{2} + 1) }^{2} - 3( \sqrt{2} + 1) + 2 \\ \\ 2 + 1 + 2\sqrt{2} - 3 \sqrt{2} - 3 + 2 \\ \\ 3 - 1 \sqrt{2} - 1 \\ \\ 2 - \sqrt{2} \\ \\ 2 - 1.4 (optional \: \: \: steps)\\ \\ 0.6 \: \:$

4 0

2 years ago

Which of the following ordered pairs belongs to the graph of f(x)

Lera25 [3.4K]

Answer:

The second choice, $(-1,\, 12)$ .

Step-by-step explanation:

Note, that the expression $y = f(x)$ is an equation. A point $(x,\, y)$ is on the graph of $y = f(x)\!$ if and only if the value of $x$ and $y$ satisfy this equation; that is: in other words, the $y\!$ -coordinate of that point (the second number in the tuple) should be equal to $f(x)$ , which is equal to $(-3\, x +9)$ (evaluated where $x\!$ is equal to the first number in the tuple.

For each tuple in the choices, calculate the value of $f(x)$ where $x$ is equal to the first number of each tuple. Compare the result to the second number in that tuple. That choice corresponds to a valid point on $y = f(x)$ only if these two numbers match.

First choice: $x = 1$ , $f(x) = f(1) = -3 + 9 = 6$ . That's not the same as the second number, $-10$ . Therefore, this point isn't on the graph of $y = f(x)$ .
Second choice: $x = -1$ , $f(x) = f(-1) = (-3)\times (-1) + 9 = 3 + 9 = 12$ . That matches the second number in the tuple. Therefore, this point is on the graph of $y = f(x)$ .
Third choice: $x = 2$ , $f(x) = f(2) = (-3)\times 2 + 9 = 3$ . That's not the same as the second number, $(-3)$ . Therefore, this point isn't on the graph of $y = f(x)$ .
Fourth choice: $x = -2$ , $f(x) = f(-2) = (-3)\times (-2) + 9 = 15$ . That's not the same as the second number, $13$ . Therefore, this point isn't on the graph of $y = f(x)$ .

4 0

3 years ago