All categories

3 years ago

Deirdre is factoring the polynomial x2 + 2x – 24. Which combination can she use to replace the middle term, 2x?

Mathematics

2 answers:

mafiozo [28]3 years ago

3 0

to replace 2x we need +6x-4x

Naddika [18.5K]3 years ago

3 0

Answer:

6x - 4x

Step-by-step explanation:

x^2 + 2x – 24

We need to find out the factors that replace the middle term +2x

Constant term is -24

coefficient of middle term is +2

We need to find out two factors whose product is -24 and sum is +2

6 times (-4) = -24

6 + ( -4) = 2

So 6 and -4 gives us product -24 and sum +2

the middle term +2x can be written as 6x - 4x

You might be interested in

63 ⋅ 73 = 423 is this correct

emmasim [6.3K]

Answer:

4599

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Please help!

maxonik [38]

Step-by-step explanation:

In ΔAPO and ΔBPO,

$AP = BP \\$ ( Length of tangents from an external point to a circle are equal)

$OA = OB$ ( Radii of same circle)

$OP = OP$ ( Common side)

∴ ΔAPO = ΔBPO (SSS Congruence) ---------------(1)

Given that, ∠AOP = 64°

∠AOP = ∠BOP [ From (1) ]

⇒∠BOP = 64

Now,

∠BOP + ∠BOD = 180° ( Linear Pair)

∠BOD = 180 - 64 (∵ ∠BOP = 64°)

∴ ∠BOD = 116°

Hope that helps!!

Please mark as Brainliest!

It took a lot of time to type it!!

7 0

3 years ago

carla is renting a canoe. It costs $80 for 2 hours and $110 for 4 hours. What is the rate of change for this situation

Cloud [144]

Take 110-80/4-2, this gives you 30/2, which is then 15. Therefore it is 15 dollars per hour

5 0

4 years ago

Read 2 more answers

Please help! Solve this

Sever21 [200]

The solution to $\left(2+\sqrt{2}\right)^{\log_2\left(x\right)}+x\left(2+\sqrt{2}\right)^{\log_2\left(x\right)} = 1 + x^2$ is x = 1

<h3>How to solve the equation?</h3>

The equation is given as:

$\left(2+\sqrt{2}\right)^{\log_2\left(x\right)}+x\left(2+\sqrt{2}\right)^{\log_2\left(x\right)} = 1 + x^2$

Split the equation as follows:

$y\ =\ \left(2+\sqrt{2}\right)^{\log_2\left(x\right)}+x\left(2+\sqrt{2}\right)^{\log_2\left(x\right)}$

$y = 1 + x^2$

Next, we plot the graph of both equations (see attachment)

From the attached graph, the intersection point is (1, 2)

Remove the y value

x = 1

Hence, the solution to $\left(2+\sqrt{2}\right)^{\log_2\left(x\right)}+x\left(2+\sqrt{2}\right)^{\log_2\left(x\right)} = 1 + x^2$ is x = 1