Company A has a sales position with a yearly salary of $42,000. Company B has a similar sales position with a slary of $39,000 plus 1% conmission on yearly sales.
Let x be the amount of yearly sales
Company A has a sales position with a yearly salary of $42,000.
yearly salary = 42,000
Company B has a similar sales position with a salary of $39,000 plus 1% commission on yearly sales.
1% is 0.01
yearly salary = 39,000+ 0.01x
yearly sales is the salary at company A greater than the salary and conmission at company B
A > B
42000 > 39000+ 0.01x
We solve the inequality
39000+ 0.01x < 42000
Subtract 39000 on both sides
0.01x < 3000
divide by 0.01
x> 300,000
For yearly sales > $300,000, the salary at company A greater than the salary and commission at company B
y = 90°
Solution:
The reference image for the answer is attached below.
The sum of opposite interior angles is equal to the exterior angles.
m∠BAC + m∠ACB = 110°
m∠BAC + 70° = 110°
m∠BAC = 110° – 70°
m∠BAC = 40°
m∠BAD + m∠DAC = 40°
x + x = 40°
2x = 40°
Divide by 2 on both sides of the equation.
x = 20°
In triangle DAC,
Sum of all the angles of a triangle = 180°
m∠DAC + m∠ACD + m∠CDA = 180°
20° + 70° + m∠CDA = 180°
90° + m∠CDA = 180°
m∠CDA = 180° – 90°
m∠CDA = 90°
∠CDA and y lies on the straight line. So they form a linear pair.
y + m∠CDA = 180°
y + 90° = 180°
y = 180° – 90°
y = 90°
The value of y is 90°.
C. 1
It's because 2/3 is equal to 0.6666667
1 is the only greater than that since they're all negative options
Answer:
take a screen shot and then post it
Step-by-step explanation:
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