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Gwar [14]
3 years ago
10

I need the awnsers for questions 1-4 on “what happened to the parent function?”

Mathematics
1 answer:
denis23 [38]3 years ago
6 0

Answer:

In all functions, a number was either added or subtracted from the total sum of y.

Step-by-step explanation:

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Given A(3, 4), B(4, 3) and C(2, 1), what are the coordinates of C', the image of C under a rotation of 90 degrees about the orig
Aleks [24]

<u>Given</u>:

The coordinates of the points A, B and C are (3,4), (4,3) and (2,1)

The points are rotated 90° about the origin.

We need to determine the coordinates of the point C'.

<u>Coordinates of the point C':</u>

The general rule to rotate the point 90° about the origin is given by

(x, y) \Rightarrow(-y, x)

Substituting the coordinates of the point C in the above formula, we get;

(2, 1) \Rightarrow(-1, 2)

Therefore, the coordinates of the point C' is (-1,2)

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4 years ago
Help easy math question!!!
bogdanovich [222]

Answer:

The length of the third side of the triangle is 30.

Step-by-step explanation:

Here is the formula for the Pythagorean Theorem:

a^{2} + b^{2} = c^{2}

The hypotenuse, based on the problem, is 50. Anyways, let's get back to calculating!

We need to multiply 40 times 40 and 50 times 50.

40 times 40, or 40 squared, equals to 1600.

50 times 50, or 50 squared, equals to 2500.

c^{2} - b^{2}  = a^{2}

Now, let's subtract. 2500 - 1600 = 900. We need to find the square root of 900--which is 30, because 30 times 30, or 30 squared, equals to 900.

8 0
3 years ago
Bring the fraction a/a-4 to a denominator of 16-a^2
Dmitry_Shevchenko [17]

Answer:

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3 0
4 years ago
PLEASE HELP:
Kryger [21]
Alright so lets start with an arbitrary amount of students. Just to help us visualize the problem.

Say, 100 students for the first year when it was founded?

So far,
1996 - 100 students

From 96' to 97', it doubles. So:
1996 - 100 students
1997 - 200 students

From 97' to 98', it doubles AGAIN.
1996 - 100 students
1997 - 200 students
1998 - 400 students

So, what the percentage increase from 100, to 400?

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3 0
3 years ago
Read 2 more answers
In a chess club the probability that Shaun will beat Mike is 3/8 .
romanna [79]

Answer:

\frac{10}{56} = 0.1786 probability that Shaun loses both games

Step-by-step explanation:

Games are independent, so we find each separate probability, and multiply them.

In a chess club the probability that Shaun will beat Mike is 3/8.

So 1 - \frac{3}{8} = \frac{8}{8} - \frac{3}{8} = \frac{5}{8} probability that Shaun loses.

The probability that Shaun will beat Tim is 5/7 .

So 1 - \frac{5}{7} = \frac{2}{7} probability that Shaun loses.

What is the probability that Shaun loses both games?

This is:

p = \frac{5}{8} \times \frac{2}{7} = \frac{5*2}{8*7} = \frac{10}{56} = 0.1786

\frac{10}{56} = 0.1786 probability that Shaun loses both games

3 0
3 years ago
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