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Gala2k [10]
3 years ago
10

Alex scored 70% in a spelling test with 20 quetions

Mathematics
2 answers:
IRISSAK [1]3 years ago
7 0

Answer:

14 right answers and 6 wrong answers

Step-by-step explanation:

To get a 70% you have to get 14 questions right and 6 wrong

amm18123 years ago
5 0

Answer:

This means that Alex answered 14 questions correctly

Step-by-step explanation:

<u>Step 1:  Find an equation</u>

20 * 0.7 = x

<u>Step 2:  Multiply</u>

20 * 0.7 = x

14 = x

Answer:  This means that Alex answered 14 questions correctly

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30x + 20y +55 ANSWER ASAP
vazorg [7]

Answer:

are there any options?

7 0
3 years ago
Can someone help its due soon
Pani-rosa [81]

Answer:

x=43

Step-by-step explanation:

80+65=145

a quadrilateral has 360 degrees

360-145=215 degrees left

3x+2x=5x

5x=215 degrees (divide by 5)

x=42

PLEASE GIVE ME BRAINLIEST!!<3

7 0
3 years ago
Using Euler's relation, derive the following relationships:a. Cosθ=½(e^jθ+e^−jθ)b. Sinθ=½(e^jθ−e(^−jθ)
Montano1993 [528]

Answer:

a. cosθ = ¹/₂[e^jθ + e^(-jθ)] b. sinθ = ¹/₂[e^jθ - e^(-jθ)]

Step-by-step explanation:

a.We know that

e^jθ = cosθ + jsinθ and

e^(-jθ) = cosθ - jsinθ

Adding both equations, we have

e^jθ = cosθ + jsinθ

+

e^(-jθ) = cosθ - jsinθ

e^jθ + e^(-jθ) = cosθ + cosθ + jsinθ - jsinθ

Simplifying, we have

e^jθ + e^(-jθ) = 2cosθ

dividing through by 2 we have

cosθ = ¹/₂[e^jθ + e^(-jθ)]

b. We know that

e^jθ = cosθ + jsinθ and

e^(-jθ) = cosθ - jsinθ

Subtracting both equations, we have

e^jθ = cosθ + jsinθ

-

e^(-jθ) = cosθ - jsinθ

e^jθ + e^(-jθ) = cosθ - cosθ + jsinθ - (-jsinθ)

Simplifying, we have

e^jθ - e^(-jθ) = 2jsinθ

dividing through by 2 we have

sinθ = ¹/₂[e^jθ - e^(-jθ)]

4 0
4 years ago
3.14*16.8*16.8*16.9
vitfil [10]

Answer: 3.14 *16.8*16.8*16.9=14977.3478

14977.3478= 14,977.35

6 0
3 years ago
Please help!!!!!!! Will mark brainliest
netineya [11]

Answer:

\displaystyle 5

Step-by-step explanation:

\displaystyle ±7 = \sqrt{49} \\ \\ -7 = x + 2\:\:AND\:\:7 = x + 2 \\ \\ -9, 5 = x

Sinse you want the POSITIVE solution, your answer is 5.

I am joyous to assist you at any time.

7 0
3 years ago
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