Let x be the length of each side of the nonagon. We then split up the nonagon into 9 congruent, isosceles triangles, each with base = x and height = 12. Then the area of each triangle is 1/2 • x • 12 = 6x, so the total area of the nonagon will be 9 • 6x = 54x.
To find x, we can use some facts from geometry and trigonometry.
• In any polygon, the sum of the measures of the exterior angles is 360°. So each of these exterior angles will measure 360°/9 = 40°.
• Exterior angles are supplementary to the interior angles. So each interior angle will measure 180° - 40° = 140°.
• Each of the 9 triangles are isosceles with base angles measuring half the interior angles of the nonagon, 140°/2 = 70°.
• Cut the triangle in half along the labeled inradius of the nonagon, which has length 12. In the resulting right triangle, we have
tan(70°) = 12 / (x/2)
and solving for x gives
tan(70°) = 24/x
x = 24/tan(70°)
x = 24 cot(70°) ≈ 8.7
Then the total area of the nonagon is
54x = 54 • 24 cot(70°) ≈ 471.7
Answer:
y=-5
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
The diagonals of a rectangle are equal and bisect each other
so
step 1
Find the value of x
substitute the given values
solve for x
Multiply by 2 both sides
step 2
Find the value of y
we have
substitute
substitute the value of x
The answer is A. To understand that, you need to put it in order by the x's and the y's to get x^2-6x + y^2-16y = -48. Now complete the square on both the x and the y terms to get (x^2-6x+9) +(y^2-16y+64) = -48+9+64. Rewriting that in vertex form on the left and doing the math on the right gives you
(x-3)^2 + (y-8)^2 = 25, which shows you a center of (3,8) and a radius of 5.
Answer:
<h2>
-27/4</h2>
Step-by-step explanation:
Given the quadratic polynomial given as g(x) = x²- 5x + 4, the zeros of the quadratic polynomial occurs at g(x) = 0 such that x²- 5x + 4 = 0.
Factorizing the resulting equation to get the roots
x²- 5x + 4 = 0
(x²- x)-(4 x + 4) = 0
x(x-1)-4(x-1) = 0
(x-1)(x-4) = 0
x-1 = 0 and x-4 = 0
x = 1 and x = 4
Since a and b are known to be the root then we can say a = 1 and b =4
Substituting the given values into the equation 1/a+1/b-2 ab
, we will have;
= 1/1 + 1/4 - 2*1*4
= 1 + 1/4 - 8
= 5/4 - 8
Find the Lowest common multiple
= (5-32)/4
= -27/4
<em>Hence the required value is -27/4</em>
