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qaws [65]
2 years ago
10

Which is a solution to x +y = 6? O (2,4) O (6,0 O (0,6) O (3,4)

Mathematics
2 answers:
olga_2 [115]2 years ago
5 0
The correct answer is [6,0] happy holidays :)
ikadub [295]2 years ago
4 0

Answer: C

Step-by-step explanation:

x+y=6

subtract x on both sides

y=-x+6

6 is the y intercept

(0,6)

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T-5 &gt;3(-2+t) <br> please help me
Vladimir79 [104]

Answer:

t < 1/2

Step-by-step explanation:

Isolate the <u>v</u><u>a</u><u>r</u><u>i</u><u>a</u><u>b</u><u>l</u><u>e</u> by dividing each side by <u>f</u><u>a</u><u>c</u><u>t</u><u>o</u><u>r</u><u>s</u> that don't contain the <u>v</u><u>a</u><u>r</u><u>i</u><u>a</u><u>b</u><u>l</u><u>e</u>.

Inequality Form: t < 1/2

Interval Notation: ( -infinity, 1/2)

3 0
2 years ago
A total of 646 tickets were sold. They were either adult ticket or student tickets. There were 54 fewer student tickets sold tha
Firdavs [7]

Answer:

350

Step-by-step explanation:

Let the number of adult tickets be x, then the number of student tickets sold would be (x–54).

We now have

x+(x–54)=646

2x=700

x=350

Therefore, 350 adult tickets were sold.

6 0
2 years ago
Graph the line with slope <br> 2<br> 5<br><br> and <br> y<br><br> -intercept <br> −<br> 7<br><br> .
tia_tia [17]

Answer:

See attachment

Step-by-step explanation:

We want to graph the line with slope

m =  \frac{2}{5}

and y-intercept ,

b =  - 7

The equation of this line is

y =  \frac{2}{5}x - 7

Starting at -7 on the y-axis, we run 5 units and rise 2 units right.

Then draw a line through the y intercept and the new point

The graph is shown in the attachment.

3 0
3 years ago
John received a 68%, 72%, and 85% on three of his math tests. After his fourth math test he now has a 79% average. What score di
Dvinal [7]

Answer:

68+72+85=225

plus 79 =304 divided by 4 = 76

plus 89 =314 divided by 4 = 78.5

plus 91=316 divided by 4 = 79

so the answer is C

plz brainlest

8 0
2 years ago
Read 2 more answers
What are the period and phase shift for f(x) = −4 tan(x − π)?
nadya68 [22]
\bf ~~~~~~~~~~~~\textit{function transformations}&#10;\\\\\\&#10;% function transformations for trigonometric functions&#10;% templates&#10;f(x)=Asin(Bx+C)+D&#10;\\\\&#10;f(x)=Acos(Bx+C)+D\\\\&#10;f(x)=Atan(Bx+C)+D&#10;\\\\&#10;-------------------

\bf \bullet \textit{ stretches or shrinks}\\&#10;~~~~~~\textit{horizontally by amplitude } A\cdot B\\\\&#10;\bullet \textit{ flips it upside-down if }A\textit{ is negative}\\&#10;~~~~~~\textit{reflection over the x-axis}&#10;\\\\&#10;\bullet \textit{ flips it sideways if }B\textit{ is negative}

\bf ~~~~~~\textit{reflection over the y-axis}&#10;\\\\&#10;\bullet \textit{ horizontal shift by }\frac{C}{B}\\&#10;~~~~~~if\ \frac{C}{B}\textit{ is negative, to the right}\\\\&#10;~~~~~~if\ \frac{C}{B}\textit{ is positive, to the left}\\\\&#10;\bullet \textit{vertical shift by }D\\&#10;~~~~~~if\ D\textit{ is negative, downwards}\\\\&#10;~~~~~~if\ D\textit{ is positive, upwards}

\bf \bullet \textit{function period or frequency}\\&#10;~~~~~~\frac{2\pi }{B}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\\\&#10;~~~~~~\frac{\pi }{B}\ for\ tan(\theta),\ cot(\theta)

with that template in mind, let's see this one.

\bf f(x)=\stackrel{A}{-4}tan(\stackrel{B}{1}x\stackrel{C}{-\pi })+\stackrel{D}{0}&#10;\\\\\\&#10;\stackrel{period}{\cfrac{2\pi }{B}\implies \cfrac{2\pi }{1}\implies 2\pi }&#10;\\\\\\&#10;\stackrel{phase/horizontal~shift}{\cfrac{C}{B}\implies \cfrac{-\pi }{1}}\implies -\pi \qquad \textit{shifted to the right by }\pi \textit{ units}
3 0
3 years ago
Read 2 more answers
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