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Semmy [17]
2 years ago
8

PLEASE I NEED HELP CLICK ON THIS IMAGE

Mathematics
2 answers:
harkovskaia [24]2 years ago
5 0

Answer:

24 miles per hour.

Step-by-step explanation:

you divide 144 by 6 to get 24.

suter [353]2 years ago
5 0

Answer:

<em>24 miles per hour</em>

Step-by-step explanation:

To find the mph rate, you just have to take the number of miles traveled, divided by the time.

So:

144 ÷ 6 = 24

Which means they were traveling at <u><em>24 miles per hour</em></u>

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Find the value of x in the equation below. 2.7+x=11.7
forsale [732]

Answer:

the answer is 9

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Can someone help plz
KIM [24]
I think the answer is B.
8 0
3 years ago
A healthy human heart beats about 1,533,000 times a year. A sparrow's heart beats about 241,776,000 times in a year. About how m
Galina-37 [17]

Answer:

About 158 times

Step-by-step explanation:

Represent the rate of human heart with H and sparrow's heart with S

H = 1,533,000\ times

S = 241,776,000\ times

Required

Determine how many times faster is S than H

To do this, we simply divide S by H i.e.

Number = \frac{S}{H}

Number = \frac{241,776,000}{1,533,000}

Number = 157.714285714

Number = 158 --- approximated

<em>Hence, the sparrow's heart beats about 158 times faster than the human hearts</em>

5 0
2 years ago
Help me pls I,need it very much
Sunny_sXe [5.5K]
A straight line is 180 degrees. As a result, 180-35=x, or x=145
3 0
3 years ago
During the first decade of the century, the population of a certain city was 145,380 in 2000 and 219,135 in 2010. Find the expon
Likurg_2 [28]

Answer:

The exponential growth function is P=145380e^{0.04103t}

Step-by-step explanation:

Given: The population of a certain city was 145,380 in 2000 and 219,135 in 2010.

To find: exponential growth function that models the growth of the city

Solution:

The exponential growth function is given by P=P_0 e^{kt}

Here, P denotes total population after time t

P_0 denotes initial population

k denotes rate of growth

t denotes time

As P(0)=145,380,

145380=P_0e^{0}\\145380=P_0\\P=145380e^{kt}

As P(10)=219135

219135=145380e^{10k}\\e^{10k}=\frac{219135}{145380}\\=1.507326\\k=\frac{1}{10}\ln (1.507326)\\=0.04103\\\Rightarrow P=145380e^{0.04103t}

8 0
3 years ago
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