Given:
The graph of triangle PQR and triangle P'Q'R'.
To find:
The transformation that will map the triangle PQR onto P'Q'R'.
Solution:
From the given graph it is clear that the triangle PQR is formed in II quadrant and its base lies on the negative direction of x-axis.
The triangle P'Q'R' is formed in IV quadrant and its base lies on the positive direction of x-axis.
This is possible it the figure is rotated 180 degrees about the origin.
Therefore, the correct option is A.
Answer:
3185
Step-by-step explanation:
The range of the given graph is [5, ∞).
Range.
Range refers the set of possible output values, and if we have the graph, then the set of all possible y values on the graph is defined as the range.
Given,
Here we have the graph.
Through the given graph we have to find the range of the line.
As per the definition of range, we have identified that the range take the value of y axis.
While we lookin into the given graph, we have identified that the starting point of the line is
=> (0, 5)
In this point 0 refers the x coordinate and 5 refers the y coordinate. So, the starting range is 5.
And the end of the line is not pointed.
So, we can consider that this line goes infinitely.
So, the range of the graph is [5, ∞).
To know more about Range here.
brainly.com/question/2709928
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Step-by-step explanation:
7 + y < 12 it can also be written as
7 + y = 12
y = 12 - 7
y = 5
or
y < 5
Hope it will help :)
Using the slope intercept formula, we can see that the slope of line p is 3/5.Since line j is perpendicular to line p it must have a slope that is the negative reciprocal(-5/3).Using the formula we can find the answer.j:y-1=-5/3(x-5)
Doing some math we get:5x+3y=28
