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Radda [10]
4 years ago
8

Last month, a dwarf lemon tree grew half as much as a semi-dwarf lemon tree. A full-size lemon tree grew three times as much as

the semi-dwarf lemon. Together, the three trees grew 27 inches. Write and solve an equation to determine how much each tree grew. Make sure you define your variable.
Mathematics
1 answer:
dimulka [17.4K]4 years ago
7 0

Answer: the dwarf tree grew by 3 inches.

the semi dwarf tree grew by 6 inches.

the full size tree grew by 18 inches.

Step-by-step explanation:

Let x represent how much the semi-dwarf lemon tree grew.

Last month, a dwarf lemon tree grew half as much as a semi-dwarf lemon tree. This means that the amount by which the dwarf lemon tree grew is expressed as x/2

A full-size lemon tree grew three times as much as the semi-dwarf lemon. This means that the amount by which the full-size lemon tree grew is expressed as 3x

Together, the three trees grew 27 inches. This means that

x/2 + x + 3x = 27

Cross multiplying by 2, it becomes

x + 2x + 6x = 54

9x = 54

x = 54/9

x = 6 inches

The dwarf tree grew by 6/2 = 3 inches.

The full-size lemon tree grew by 3 × 6 = 18 inches

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X varíes directly with y and z. X =1200 when y =20 and z=30 find x when y=10 and z=20
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Answer:

Value of x = 400

Step-by-step explanation:

Joint variation states that describes a situation where a variable depends on two (or more) other variables, and varies directly with some of them.

Given: x varies directly with y and  z.

i.e x \propto y and x \propto z

then we have the joint variation as;

x = k yz ......[1] where k is the constant variation.

Substitute the value of x =1200 when y =20 and z = 30 to solve for k;

1200 = k (20)(30)

Simplify:

1200 = 600k

Divide both sides by 600 we get;

k = 2

Now, substitute k =2 , y =10 and z = 20 to find x;

Using [1] we have;

x = 2 \times (10)(20) = 2 \times 200

Therefore, the value of x is, 400



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