Question

Find the quotient of the quantity negative 40 times x to the 3rd power minus 12 times x to the 2nd power plus 16 times x all over negative 4 times x.

Answer 1

Answer:

quotient is $10x^2+3x-4$

Step-by-step explanation:

$\frac{-40x^3-12x^2+16x}{-4x}$

To find the quotient we divide each term by -4x

$\frac{-40x^3}{-4x} =10x^2$

Negative and negative becomes positive.

$\frac{-12x^2}{-4x} =3x$

$\frac{-16x}{-4x} =-4$

$\frac{-40x^3-12x^2+16x}{-4x}=10x^2+3x-4$

Answer 2

-10x^2-3x+4

Hope this helps