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3 years ago

14

Find the quotient of the quantity negative 40 times x to the 3rd power minus 12 times x to the 2nd power plus 16 times x all ove

r negative 4 times x.

2 answers:

nikitadnepr [17]3 years ago

8 0

Answer:

quotient is $10x^2+3x-4$

Step-by-step explanation:

$\frac{-40x^3-12x^2+16x}{-4x}$

To find the quotient we divide each term by -4x

$\frac{-40x^3}{-4x} =10x^2$

Negative and negative becomes positive.

$\frac{-12x^2}{-4x} =3x$

$\frac{-16x}{-4x} =-4$

$\frac{-40x^3-12x^2+16x}{-4x}=10x^2+3x-4$

Taya2010 [7]3 years ago

5 0

-10x^2-3x+4

Hope this helps

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Mars2501 [29]

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4 years ago

Una bacteria se reproduce por biparticion cada 15 minutos. ¿Cuantas bacterias al cabo de 6 horas?

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3 years ago

Use the Square Root Property to solve the quadratic equation c2+12c+36=121

Alexxandr [17]

Using the Square Root Property to solve the quadratic equation we have

c = 5,-17.

<h3>What is Square Root Property?</h3>

Simply put, the square root property asserts that if one side of an equation is a perfect square and the other is a number, then we can solve the problem by taking the square root of both sides and then adding a plus or minus sign to the side containing the number.

Generally, the quadratic equation is mathematically given as

c2+12c+36 = 121

Therefore

(c+6)2 = (11)2

(c+6) = 11 or (c+6) = -11

c = 11-6

Hence, the roots of the equation are

c = 5 or c= -17

In conclusion, the solution for the quadratic equation is

c = 5,-17.

Read more about Square Root Property

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2 years ago

2 u + 12 < 23<br> 0,1 d + 8 > 0<br> 3 - 4 r > 7<br> 13 < 2 z + 3<br> 6 ≥ 9 - 0, 15 i

BartSMP [9]

Answer:

Part 1) $u< 5.5$

Part 2) $d > -80$

Part 3) $r < -1$

Part 4) $z>5$

Part 5) $i\geq 20$

Step-by-step explanation:

<u><em>The question is</em></u>

Solve each inequality for the indicated variable

Part 1) we have

$2u+12$

subtract 12 both sides

$2u< 23-12\\2u$

Divide by 2 both sides

$u< 5.5$

The solution is the interval (-∞,5.5)

In a number line the solution is the shaded area at left of u=5.5 (open circle)

The number 5.5 is not included in the solution

Part 2) we have

$0.1d+8 >0$

subtract 8 both sides

$0.1d > -8$

Divide by 0.1 both sides

$d > -80$

The solution is the interval (-80,∞)

In a number line the solution is the shaded area at right of d=-80 (open circle)

The number -80 is not included in the solution

Part 3) we have

$3-4r> 7$

Subtract 3 both sides

$-4r>7-3\\-4r>4$

Divide by -4 both sides

Remember that, when you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality symbol

$r < -1$

The solution is the interval (-∞,-1)

In a number line the solution is the shaded area at left of r=-1.1 (open circle)

The number -1.1 is not included in the solution

Part 4) we have

$13< 2z+3$

Subtract 3 both sides

$13-3$

Divide by 2 both sides

$5$

Rewrite

$z>5$

The solution is the interval (5,∞)

In a number line the solution is the shaded area at right of z=5 (open circle)

The number 5 is not included in the solution

Part 5) we have

$6\geq 9-0.15i$

Subtract 9 both sides

$6-9\geq -0.15i\\-3\geq -0.15i$

Divide by -0.15 both sides

Remember that, when you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality symbol

$20\leq i$

Rewrite

$i\geq 20$

The solution is the interval [20,∞)

In a number line the solution is the shaded area at right of i=20 (closed circle)

The number 20 is included in the solution

6 0

4 years ago

Find the difference 145,874-90,000 (finacial mathematics)

kiruha [24]

Answer:

55,874

Step-by-step explanation:

Just subtract

143,874 - 90,000

5 0

4 years ago

Read 2 more answers