All categories

3 years ago

If cscØ=8/7, which equation represents cotØ?

Mathematics

1 answer:

Sergeeva-Olga [200]3 years ago

3 0

Answer:

2nd one

Step-by-step explanation:

I believe it s number 2 the scevjj

You might be interested in

YEAR 9 MATHEMATUCS ALGEBRA

WINSTONCH [101]

Answer:

Your answer is :

B. 6a^2 + 3ab

Markn my answer as brainlist . Follow me for more answer.

Step-by-step explanation:

7 0

2 years ago

Two tailors, Valentina and Laura, sit down to do some embroidery. Valentina can embroider 2 shirts per hour, and Laura can get t

mina [271]

Answer:

Valentina and Laura finished the same total number of shirts in $4$ hours.

Total number of shirts finished by Valentina $=23$

Total number of shirts finished by Laura $=23$

Step-by-step explanation:

Suppose that Valentina and Laura finished the same total number of shirts in $t$ hours.

Valentina can embroider 2 shirts per hour and Valentina has already completed 15 shirts.

Total number of shirts finished by Valentina $=2t+15$

Laura can get through 3 shirts per hour and Laura has completed 11 shirts.

Total number of shirts finished by Laura $=3t+11$

Therefore,

$2t+15=3t+11\\3t-2t=15-11\\t=4$

So,

Valentina and Laura finished the same total number of shirts in $4$ hours.

Total number of shirts finished by Valentina $=2(4)+15=8+15=23$

Total number of shirts finished by Laura $=3(4)+11=12+11=23$

6 0

2 years ago

1+-w2+9w and I need help cuz I’m on 76 and I’m sooo close help

Gnesinka [82]

$\huge \boxed{\mathfrak{Question} \downarrow}$

Simplify :- 1 + - w² + 9w.

$\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}$

$\large \sf1 + - w ^ { 2 } + 9 w$

Quadratic polynomial can be factored using the transformation $\sf \: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right)$ , where $\sf x_{1} and x_{2}$ are the solutions of the quadratic equation $\sf \: ax^{2}+bx+c=0$ .

$\large \sf-w^{2}+9w+1=0$

All equations of the form $\sf\:ax^{2}+bx+c=0$ can be solved using the quadratic formula: $\sf\frac{-b±\sqrt{b^{2}-4ac}}{2a}$ . The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

$\large \sf \: w=\frac{-9±\sqrt{9^{2}-4\left(-1\right)}}{2\left(-1\right)} \\$

Square 9.

$\large \sf \: w=\frac{-9±\sqrt{81-4\left(-1\right)}}{2\left(-1\right)} \\$

Multiply -4 times -1.

$\large \sf \: w=\frac{-9±\sqrt{81+4}}{2\left(-1\right)} \\$

Add 81 to 4.

$\large \sf \: w=\frac{-9±\sqrt{85}}{2\left(-1\right)} \\$

Multiply 2 times -1.

$\large \sf \: w=\frac{-9±\sqrt{85}}{-2} \\$

Now solve the equation $\sf\:w=\frac{-9±\sqrt{85}}{-2}$ when ± is plus. Add -9 to $\sf\sqrt{85}$ .

$\large \sf \: w=\frac{\sqrt{85}-9}{-2} \\$

Divide -9+ $\sf\sqrt{85}$ by -2.

$\large \boxed{ \sf \: w=\frac{9-\sqrt{85}}{2}} \\$

Now solve the equation $\sf\:w=\frac{-9±\sqrt{85}}{-2}$ when ± is minus. Subtract $\sf\sqrt{85}$ from -9.

$\large \sf \: w=\frac{-\sqrt{85}-9}{-2} \\$

Divide $\sf-9-\sqrt{85}$ by -2.

$\large \boxed{ \sf \: w=\frac{\sqrt{85}+9}{2}} \\$

Factor the original expression using $\sf\:ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right)$ . Substitute $\sf\frac{9-\sqrt{85}}{2}$ for $\sf\:x_{1}$ and $\sf\frac{9+\sqrt{85}}{2}$ for $\sf\:x_{2}$ .

$\large \boxed{ \boxed {\mathfrak{-w^{2}+9w+1=-\left(w-\frac{9-\sqrt{85}}{2}\right)\left(w-\frac{\sqrt{85}+9}{2}\right) }}}$

Well, in the picture you inserted it says that it's 8th grade mathematics. So, I'm not sure if you have learned simplification with the help of biquadratic formula. So, if you want the answer simplified only according to like terms then your answer will be ⇨

$\large \sf \: 1 + - w {}^{2} + 9w \\ =\large \boxed{\bf \: 1 - {w}^{2} + 9w}$

This cannot be further simplified as there are no more like terms (you can use the biquadratic formula if you've learned it.)

4 0

2 years ago

What is the area of the triangle?

Luda [366]

Answer:

270cm^2

Step-by-step explanation:

The side length is irrelevant and does not matter.

The area of a triangle is found by multiplying the base by the height and then dividing that by two.

For this problem it would be...

30*18=540

540/2=270

So the area would be 270cm^2

3 0

3 years ago

Which challenge in western Texas did Sam Houston face after becoming President of

boyakko [2]

Answer: Minister from the newly recognized republic the fol- ... annex Texas. They did not want to face that ... in recognizing the independence of Texas and, in supplement and obtained at the hands of one of the most ... of President Houston, in his message of the 5th of ...... the city of Washington, which proposition, after having.

6 0

3 years ago