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Olegator [25]
3 years ago
6

Add 7 and y, then add z to the result

Mathematics
1 answer:
Illusion [34]3 years ago
6 0

(7+y)+z

Step-by-step explanation:

this is to separate the sum of 7 and y from z

You might be interested in
Jimmy thought he had purchased 7 folders, but purchased 6. What was his percent error?
OleMash [197]

Answer:

Step-by-step explanation:

Percent Error = | Actual Yield-Theoretical/ Theoretical Yield | *100%

Error= |-1/7|*100%= 14.29%

4 0
3 years ago
A set of five integers contains 1 , 3 , and 22 . what other two integers must be included in this set so that the mean of all fi
d1i1m1o1n [39]
Total number of integers = 5

median
= (5+1)/2 th observation
= 3 rd observation

therefore the 3rd number = 13

now let the other number be x

total sum = 1+3+13+x+22 = 39+x

ATQ

(39+x)/5 = 16

39+x = 80

x = 41

the numbers are -

1,3,13,22,41
8 0
3 years ago
ПОЖАЛУЙСТА ПОМОГИТЕ РЕШИТЬ ДАЮ 23 ОЧКА!!!
posledela

(Простите, пожалуйста, мой английский. Русский не мой родной язык. Надеюсь, у вас есть способ перевести это решение. Если нет, возможно, прилагаемое изображение объяснит достаточно.)

Use the shell method. Each shell has a height of 3 - 3/4 <em>y</em> ², radius <em>y</em>, and thickness ∆<em>y</em>, thus contributing an area of 2<em>π</em> <em>y</em> (3 - 3/4 <em>y</em> ²). The total volume of the solid is going to be the sum of infinitely many such shells with 0 ≤ <em>y</em> ≤ 2, thus given by the integral

\displaystyle 2\pi \int_0^2 y \left(3-\frac34 y^2\right) \,\mathrm dy = 2\pi \left(\frac32 y^2 - \frac3{16} y^4\right)\bigg|_0^2 = 6\pi

Or use the disk method. (In the attachment, assume the height is very small.) Each disk has a radius of √(4/3 <em>x</em>), thus contributing an area of <em>π</em> (√(4/3 <em>x</em>))² = 4<em>π</em>/3 <em>x</em>. The total volume of the solid is the sum of infinitely many such disks with 0 ≤ <em>x</em> ≤ 3, or by the integral

\displaystyle \pi \int_0^3 \left(\sqrt{\frac43x}\right)^2 \,\mathrm dx = \frac{2\pi}3 x^2\bigg|_0^3 = 6\pi

Using either method, the volume is 6<em>π</em> ≈ 18,85. I do not know why your textbook gives a solution of 90,43. Perhaps I've misunderstood what it is you're supposed to calculate? On the other hand, textbooks are known to have typographical errors from time to time...

8 0
3 years ago
Please help it’s pretty easy and I’ll reward brainiest
Julli [10]
A, hope this helps!!
8 0
3 years ago
I have 47 nickels and dimes worth $4.20. How many of each type of coin do I have?
soldi70 [24.7K]

Answer:

37 dimes and 10 nickels

Step-by-step explanation:

let d = # dimes

let n = # nickels

we can set up a system of equations:

n + d = 47

.05n + .10d = 4.2

if we solve the first equation for 'n' we get:  

n = 47-d

now we can substitute this in for 'n' in the second equation:

.05(47-d) + .10d = 4.2

2.35 - .05d + .10d = 4.2

2.35 + .05d = 4.2

subtract 2.35 from each side to get:

.05d = 1.85

d = 1.85÷.05

d = 37

if d+n = 47 and d=37 then n = 10

Check:

.05(10) + .1(37) should equal 4.2

.50 + 3.7 = 4.2  [It Checks Out]

6 0
2 years ago
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