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sukhopar [10]
3 years ago
7

For this question you must Answer A B and C

Mathematics
2 answers:
Lorico [155]3 years ago
5 0
Idk sorry, but use Socratic it works as well
Dimas [21]3 years ago
4 0

Answer: Idk but try downloading more apps it’s a lot easier to have more than one

Step-by-step explanation:

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Someone explain it please
Alina [70]

9514 1404 393

Answer:

  ∠A = 44°

Step-by-step explanation:

In order to find the measure of angle A, you need to know the value of the variable x. This means you need some relation that you can solve to find x.

Happily, that relation is "the sum of angles in a triangle is 180°." This means ...

  84° +(x +59)° +(x +51)° = 180°

  (2x + 194)° = 180° . . . collect terms

  2x = -14 . . . . . . . . . . divide by °, and subtract 194

  x = -7 . . . . . . . . . . . .divide by 2

Now, the measure of angle A is ...

  ∠A = (x +51)° = (-7 +51)°

  ∠A = 44°

4 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx%2B1%7D%7Bx-4%7D%20-%5Cfrac%7Bx%2B1%7D%7Bx%5E%7B2%7D%20%5E%7D-7x%2B12" id="TexFormu
oksian1 [2.3K]
(x+1)/(x-3) hope this helps!
5 0
2 years ago
Victoria works at the Apple Store. She is paid
Greeley [361]

Answer:

hdjebejdbydvdfdvgdgbehdbdjgdjd

4 0
3 years ago
Read 2 more answers
A wire b units long is cut into two pieces. One piece is bent into an equilateral triangle and the other is bent into a circle.
mezya [45]
1. Divide wire b in parts x and b-x. 

2. Bend the b-x piece to form a triangle with side (b-x)/3

There are many ways to find the area of the equilateral triangle. One is by the formula A= \frac{1}{2}sin60^{o}side*side=   \frac{1}{2} \frac{ \sqrt{3} }{2}  (\frac{b-x}{3}) ^{2}= \frac{ \sqrt{3} }{36}(b-x)^{2}
A=\frac{ \sqrt{3} }{36}(b-x)^{2}=\frac{ \sqrt{3} }{36}( b^{2}-2bx+ x^{2}  )=\frac{ \sqrt{3} }{36}b^{2}-\frac{ \sqrt{3} }{18}bx+ \frac{ \sqrt{3} }{36}x^{2}

Another way is apply the formula A=1/2*base*altitude,
where the altitude can be found by applying the pythagorean theorem on the triangle with hypothenuse (b-x)/3 and side (b-x)/6

3. Let x be the circumference of the circle.

 2 \pi r=x

so r= \frac{x}{2 \pi }

Area of circle = \pi  r^{2}= \pi  ( \frac{x}{2 \pi } )^{2} = \frac{ \pi }{ 4 \pi ^{2}  }* x^{2} = \frac{1}{4 \pi } x^{2}

4. Let f(x)=\frac{ \sqrt{3} }{36}b^{2}-\frac{ \sqrt{3} }{18}bx+ \frac{ \sqrt{3} }{36}x^{2}+\frac{1}{4 \pi } x^{2}

be the function of the sum of the areas of the triangle and circle.

5. f(x) is a minimum means f'(x)=0

f'(x)=\frac{ -\sqrt{3} }{18}b+ \frac{ \sqrt{3} }{18}x+\frac{1}{2 \pi } x=0

\frac{ -\sqrt{3} }{18}b+ \frac{ \sqrt{3} }{18}x+\frac{1}{2 \pi } x=0

(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) x=\frac{ \sqrt{3} }{18}b

x= \frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }

6. So one part is \frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) } and the other part is b-\frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }

4 0
3 years ago
Read 2 more answers
A city is designing a new trail system that will be
lyudmila [28]

Step-by-step explanation:

the answer is 6.125 and its will be divided by 125

3 0
3 years ago
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