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nekit [7.7K]
4 years ago
13

Find (f•g)(1) f(x)= x^2-1 g(x)=sqrt x

Mathematics
1 answer:
Anastaziya [24]4 years ago
7 0

Answer:

0

Step-by-step explanation:

So we have the two functions:

f(x)=x^2-1\text{ and } g(x)=\sqrt x

And we want to find:

(f\cdot g)(1)

This is the same as:

=f(1)\cdot g(1)

So, let's find f(1) and g(1):

f(1)=(1)^2-1

Square:

f(1)=1-1

Subtract:

f(1)=0

g(1)=\sqrt1

Evaluate:

g(1)=1

So:

(f\cdot g)(1)=f(1)\cdot g(1)=0\cdot1

Multiply:

=0

So, our answer is 0.

And we're done!

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Answer:

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1a: (d)

4o: (b)

Step-by-step explanation:

2a: the equation of a circle circumference needs to be transformable to the form (x-x_C)^2 + (y - y_C)^2 = r^2 where C(x_C; y_C) is the center and <em>r</em> is the radius. (a) and (d) can’t be it because they contain non-zero factors on <em>xy</em>. (b) isn’t an equation.

5o: just put the given (<em>x</em>, <em>y</em>) into the equations and see if it holds. (2, 3) isn’t on the circumference of (1) because 2^2+3^2-2\cdot 2 -4\cdot 3 + 4 = 1 \neq 0, (3, 1) isn’t on it either because 3^2 + 1^2 - 2\cdot 3 - 4\cdot 1 + 4 = 4 \neq 0.

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1a: see definition from 2a. Here, r^2 = 9.

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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