If the side of square P is x and the side of square Q is y, we have x+y=26. In addition, 3*the perimeter of P+8*4y=3*4x+32y=12x+32y=492.
We have
x+y=26
12x+32y=492
Multiplying the first equation by -12 and adding it to the second, we get
20y=180 and dividing by 20 we get y=9. Plugging it into the first equation, we get 26-9=17=x. Since the area of square P is x^2 and Q is y^2,
x^2+y^2=19^2+7^2=410=the sum of the squares
So, you already know that angle CBD is 68 degrees, and the complementary angle to angle CBD is angle CBA. These angles together make 180 degrees because segment DBA is a straight line consisting of angles CBD and CBA. 180-68(the angle you already know) is 112 degrees for angle CBA. Then you repeat this process to find the other angles
Answer:
L=16 W=7
Step-by-step explanation:
P=2(L+W)
L=2W+2
46=2(2W+2)+2W
(((7×2)+2)=16×2=32
(16-2)/2=7×2=14
32+14=46 or 16+16+7+7=46
His mistake is he didn't make 6/10 to 60/100 he added them without changing the 6/10
