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Jlenok [28]
4 years ago
8

according to charles law when the temp of a gas is increased at a constant pressure it volume will ______________

Physics
1 answer:
Aliun [14]4 years ago
5 0
<span>According to Charles' law when the temp of a gas is increased at a constant pressure it volume will increase.
You're welcome.</span>
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A. static discharge <span>Static discharge is the sudden flow of electricity between two electrically charged objects caused by contact, an electrical short, or dielectric breakdown.</span>
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How to calculate the slope of position time graph?
Mashcka [7]

Answer:

The slope of a position-time graph can be calculated as:

m=\frac{\Delta y}{\Delta x}

where

\Delta y is the increment in the y-variable

\Delta x is the increment in the x-variable

We can verify that the slope of this graph is actually equal to the velocity. In fact:

\Delta y corresponds to the change in position, so it is the displacement, \Delta s

\Delta x corresponds to the change in time \Delta t, so the time interval

Therefore the slope of the graph is equal to

m=\frac{\Delta s}{\Delta t}

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3 years ago
Betty made a simple electromagnet using just a battery and a wire. What could Betty do to increase the strength of her
8090 [49]

Answer:

Coil the wire around a nail.

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3 0
3 years ago
A flywheel in the form of a uniformly thick disk of radius 1.93 m has a mass of 92.1 kg and spins counterclockwise at 419 rpm. C
Harman [31]

Answer:

Torque = 99.48 N-m²

Explanation:

It is given that,

Radius of the flywheel, r = 1.93 m

Mass of the disk, m = 92.1 kg

Initial angular velocity, \omega_i=419\ rpm=43.87\ rad/s

Final angular speed, \omega_f=0

We need to find the constant torque required to stop it in 1.25 min, t = 1.25 minutes = 75 seconds

Torque is given by :

\tau=I\times \alpha...........(1)

I is moment of inertia, for a solid disk, I=\dfrac{mr^2}{2}

\alpha is angular acceleration

I=\dfrac{92.1\ kg\times (1.93\ m)^2}{2}=171.53\ kgm^2..............(2)

Now finding the value of angular acceleration as :

\omega_f=\omega_i+\alpha t

0=43.87+\alpha \times 75

\alpha =-0.58\ m/s^2..........(3)

Using equation (2) and (3), solve equation (1) as :

\tau=171.53\ kgm^2\times -0.58\ m/s^2

\tau=-99.48\ N-m^2

So, the torque require to stop the flywheel is 99.48 N-m². Hence, this is the required solution.

8 0
3 years ago
an object at rest requires a force of 15 newtons to set it into motion. The force is greater than which force?​
Simora [160]

Answer:

Friction

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