Explanation:
that was very good question thanks for asking.
Answer:
the force exerted on the dipole = 0.11 N
Explanation:
Using F = (KQq/r^2) sin ∅
the distance of dipole to the line charge will be 30 cm, hence 1 st charge on the dipole -10 micro C is 29 cm and that to + 10 micro C is 31 cm (2 cm apart).
0.91 N with -ve charge and 0.80 to +ve charge. The difference is the force on the dipole i.e 0.11 N
Answer:
Explanation:
Given
object distance u = 3 m (- ve)
Focal length f = .05 m ( + ve )
Lens formula ,
1 / v - 1 / u = 1 / f
1 / v + 1/3 = 1 / .05
1 / v = 1 / .05 - 1 / 3
1 / v = 20 -0 .333
= 19.667
v = 1 /19.667
v = .05 m = 5 cm.
magnification = v / u = .05 / 3
size of image = ( .05 / 3) x 1.75 = 2.9 cm.
Answer:
Total moment of inertia when arms are extended: 1.613
Explanation:
This second part of the problem could be a pretty complex one, but if they expect you to do a simple calculation, which is what I imagine, the idea is just adding another moment of inertia to the first one due to the arms extended laterally and use the moment of inertia for such as depicted in the image I am attaching.
In that image:
L is the length from one end to the other of the extended arms (each 0.75m from the center of the body) which gives 1.5 meters.
m is the mass of both arms. That is: twice 5% of the mass of the person: which mathematically can be written as: 2 * 0.05 * 56.5 = 5.65 kg
Therefore this moment of inertia to be added can be obtained using the formula shown in the image:
Now, one needs to add this to the previous moment that you calculated, resulting in:
0.554 + 1.059 = 1.613
Answer:
The first and third one
Explanation:
The roughness of the surfaces is very important when determining friction as well as the force pressed on a surfaces as it helps increase friction.
HOPE IT HELPED