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Lisa [10]
3 years ago
12

A plane fillies along a straight line path after taking off and it ends up 220 km farther east and 110km farther north relative

to where it started what is the planes displacement?
A. 141km

B. 250km

C. 110km

D. 330km
Physics
1 answer:
DENIUS [597]3 years ago
3 0
330km hope this helped you.
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A furlong is 220 yd. A fortnight is 2 weeks. Convert a speed of one furlong per fortnight to millimeters per second.
nlexa [21]

Answer:

0.1663\frac{mm}{s}

Explanation:

You need to convert furlongs to yards to mm:

\frac{1 furlong}{1 fortnight}*\frac{220 yd}{1 furlong}*\frac{0.9144m}{1yd}*\frac{1000mm}{1m} = \frac{201168 mm}{1 fortnight}

Now, we convert fortnight to seconds:

\frac{201168 mm}{1 fortnight}*\frac{1 fortnight}{2 weeks}*\frac{1 week}{7 days} *\frac{1 day}{24 h}*\frac{1 h}{3600s}  = 0.1663\frac{mm}{s}

5 0
3 years ago
Three sticks are arranged to form a right triangle. If the lengths of the three sticks are 0.47 m, 0.62 m and 0.78 m, what are t
DanielleElmas [232]
Your answer is D) 90, 53, and 37.
5 0
2 years ago
How much brighter is a Sun-like star than the reflected light from a planet orbiting around it?
zloy xaker [14]

Answer:

E) a billion times brighter

Explanation:

  • <u>The sun is a star, which is about billion times brighter as the reflected light from any planet orbiting around it. </u>
  • The brightness is based on its composition and its position from the planet. The sun happens to be the brightest star on the Earth's sky which is about 13 billion times brighter than the next brightest star.
8 0
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A ball starts from rest and undergoes uniform acceleration of 2.50m/s^2. What is the velocity of the ball 4s later?
erica [24]

Explanation:

Given:

v₀ = 0 m/s

a = 2.50 m/s²

t = 4 s

Find: v

v = at + v₀

v = (2.50 m/s²) (4 s) + 0 m/s

v = 10 m/s

4 0
3 years ago
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A horizontal uniform bar of mass 2.7 kg and length 3.0 m is hung horizontally on two vertical strings. String 1 is attached to t
Jlenok [28]

Answer:

14.36 N

Explanation:

T_{1} = Tension in string 1

T_{2} = Tension in string 2

m_b = mass of the bar = 2.7 kg

W_b = weight of the bar

weight of the bar is given as

W_b = m_{b} g = (2.7) (9.8) = 26.46N

m_m = mass of the bar = 1.35 kg

W_m = weight of the monkey

weight of the monkey is given as

W_m = m_{m} g = (1.35) (9.8) = 13.23N

Using equilibrium of torque about left end

W_{m} (AB) + W_{b} (AB) = T_{2} (AC)\\W_{m} (AB) + W_{b} (AB) = T_{2} (AD - CD)\\(13.23) (1.5) + (26.46)(1.5) = T_{2} (3 - 0.65)\\\\T_{2} = 25.33 N

Using equilibrium of force in vertical direction

T_{1} + T_{2} = W_{b} + W_{m}\\T_{1} + 25.33 = 26.46 + 13.23\\T_{1} = 14.36 N

7 0
3 years ago
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