Answer:
a. 5,040 ways
b. 210 ways
Step-by-step explanation:
a) We want to pick 4 numbers out of 10 given that orders matter
If orders do matter, it will be a permutation problem
Mathematically;
n P r = n!/(n-r)!
In this case, n is 10 and r is 4
Thus, we have it that;
10 P 4 = 10!/(10-4)! = 5,040
b) if orders do not matter
It will be a combination problem
n C r = n!/(n-r)!r!
n = 10 and r = 4
10 C 4 = 10! /(10-4)!4!
= 210
M < 7 / 12
(1) < 7 / 12
(1) < 0.583333333 (false statement)
(-1) < 7 / 12
(-1) < 0.583333333 (true statement)
(-9) < 7 / 12
(-9) < 0.583333333 (true statement)
(-5) < 7 / 12
(-5) < 0.583333333 (true statement)
B C D maybe?
1 cube= 1 unit
1 Rod (Long)= 10 units
10 Rods (Longs)= 1 flat (1 flat=100 units)
10 flat =1 cube(1 cube=1000 units)
83×10= 830
2×10=20
830×20= 16,600
Just wanted to add more to help you understand why 83 is multiplied by ten and 2 is multiplied by 10. Its because when we use Base ten blocks, tens represent 1 Rod (Long)= 10 units. Hope it helps more.
Hmmm, I'm guessing your asking if that's correct, if so, yes